For the trapezoid below, what is the correct term for RT?
1 answer:
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Step-by-step answer:
Referring to the attached diagram, the resultant of two forces each with magnitude F and inclined to each other at 2a equals
Ra = 2Fcos(a) ..............................(1)
Similarly, the resultant of two forces each with magnitude F and inclined to each other at 2b equals
Rb = 2Fcos(b)..............................(2)
We are given that
Ra = 2Rb ....................................(3)
Substitute (1) & (2) in (3) gives
2Fcos(a) = 2(2Fcos(b))
Expand
2Fcos(a) = 4Fcos(b)
Simplify
cos(a) = 2 cos(b) QED
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For the first question, the total is 240 so that goes in front of the equals sign. he has already worked 97 hours, so the expression on the right begins with 97 and adds the unknown number of hours, <em>h</em>, to it:
240 = 97 + <em /><em>h</em>
For the second question, there is no graph so I cannot answer it.
3rd question: no image, can't answer.
4th question:
Use a factor tree:
240
/ \
10*24
/\ /\
5*2 *8*3
/ / /\ \
5 * 2 *4*2 *3
/ / /\ \ \
5 * 2 *2*2 * 2 * 3
Starting with the smallest factor and using exponents we have
240 = 97 + <em /><em>h</em>
For the second question, there is no graph so I cannot answer it.
3rd question: no image, can't answer.
4th question:
Use a factor tree:
240
/ \
10*24
/\ /\
5*2 *8*3
/ / /\ \
5 * 2 *4*2 *3
/ / /\ \ \
5 * 2 *2*2 * 2 * 3
Starting with the smallest factor and using exponents we have