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3 years ago

NEED ANSWER ASAP TYY SO MUCH IN ADVANCE

Mathematics

2 answers:

ratelena [41]3 years ago

8 0

Answer:

13.70

Step-by-step explanation:

a^2+b^2=c^2

a = side 1

b = side 2

c = hypotenuse

9.2^2 + b^2 = 16.5^2

272.25 - 84.64 = 187.61 =b^2

√187.61 = b = 13.697 = 13.70

STALIN [3.7K]3 years ago

5 0

Answer:

see I hope u understand

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3 years ago

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Please solve the eqution<br> Cos4x + cos2x - 2 =0

horrorfan [7]

cos4x = cos2x

We know that:

cos2x = 1-2cos^2 x

==> cos4x = 1-2cos^2 (2x)

Now substitute:

==> 1-2cos^2 (2x) = cos2x

==> 2cos^2 (2x) + cos2x - 1 = 0

Now factor:

==> (2cos2x -1)(cos2x + 1) = 0

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6 0

3 years ago

3x - 3y = 9 and x + 3y = 12 <br> Elimination

Firlakuza [10]

Answer:

$x=5.25,y=2.25$

Step-by-step explanation:

We can add the two equations to eliminate the variable $y$ and solve for $x$ :

$3x-3y+x+3y=9+12$

$4x=21$

$x=5.25$

Now, we can use substitution to solve for $y$ :

$x+3y=12$ (given)

$5.25+3y=12$

$3y=12-5.25$

$=6.75$

$y=2.25$

Hope this helps :)

8 0

3 years ago

I need help To find gradient and y-intercept...

suter [353]

Answer:

a) the gradient of the linear graph is: $\mathbf{\frac{-1}{3} }$

b) the y-intercept of linear graph is -1

Step-by-step explanation:

a) Find the gradient of the linear graph.

The formula used to find gradient is same as slope

$Gradient=\frac{Change \ in \ y \ coordinate}{Change \ in \ x \ coordinate}\\or\\Gradient=\frac{y_2-y_1}{x_2-x_1}$

Take any 2 points from the graph.

I will take: (-3,0) and (0,-1)

Putting values in formula and finding gradient

$Gradient=\frac{y_2-y_1}{x_2-x_1} \\Gradient=\frac{-1-0}{0-(-3)} \\Gradient=\frac{-1}{3}$

So, the gradient of the linear graph is: $\mathbf{\frac{-1}{3} }$

b) Find the y-intercept of linear graph

The y-intercept of linear graph is the value of y at the point where the line crosses the y axis.

So, in the given graph, that point is -1

So, the y-intercept of linear graph is -1

3 0

3 years ago