Let the initial point of the vector be (x,y). Then the magnitude of the vector v can be written as:

The magnitude of vecor v is given to be 10. So we can write:

Now from the given options, we have to check which one satisfies the above equation. That point will be the initial point of the vector.
The point in option d, satisfies the equation.
Thus, the answer to this question is option D
Answer: (x – 1)(x + 1)(x + 5) = 0
x – 1 = 0, so x = 1
x + 1 = 0, so x = -1
x + 5 = 0, so x = -5
Answer:
-14
Step-by-step explanation:
difference between -20 and -5 = 15
15 x 2/5 = 30/5 = 6
-20 + 6 = -14
Explanation:
For the purpose of filling in the table, the BINOMPDF function is more appropriate. The table is asking for p(x)--not p(n≤x), which is what the CDF function gives you.
If you want to use the binomcdf function, the lower and upper limits should probably be the same: 0,0 or 1,1 or 2,2 and so on up to 5,5.
The binomcdf function on my TI-84 calculator only has the upper limit, so I would need to subtract the previous value to find the table entry for p(x).