Variance = summation of (x - mean)^2 all divided by the number of dataset.
mean = (17 + 5 + 11 + 1 + 11)/5 = 9
Variance = [(17 - 9)^2 + (5 - 9)^2 + (11 - 9)^2 + (1 - 9)^2 + (11 - 9)^2]/5 = (8^2 + (-4)^2 + 2^2 + (-8)^2 + 2^2}/5 = (64 + 16 + 4 + 64 + 4)/5 = 152/5 = 30.4
Answer:
(4, -2)
Step-by-step explanation:
Given a point R (-2,5), if the point R' is described by a translation of 6 units to the rights and 7 units down, then the coordinate of R' will be;
6 units to the rights is towards the positive x axis
7 units down is towards the negative y axis
R' = (-2+6, 5-7)
R' = (4, -2)
Hence the coordinate point of R' on the plane is (4, -2)
Answer:
Step-by-step explanation:
we know that
The <u>distance formula</u> is derived by creating a triangle and using the Pythagorean theorem to find the length of the hypotenuse. The hypotenuse of the triangle is the distance between the two points
The formula to calculate the distance between two points is equal to
we have
A(1, 1) and B(7, −7)
Let
(x1,y1)=A(1, 1)
(x2,y2)=B(7, −7)
substitute the given values in the formula
(3,51)(5,59)
slope = (59 - 51) / (5 - 3) = 8/2 = 4
y = mx + b
slope(m) = 4
(3,51)...x = 3 and y = 51
sub and find b, the y int
51 = 4(3) + b
51 = 12 + b
51 - 12 = b
39 = b
so ur equation is : y = 4x + 39...but u need it in standard form
y = 4x + 39
-4x + y = 39
4x - y = -39 <==== this is ur equation...x = number of hrs and y = total velocity
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ur x axis is the number of hrs
ur y axis is total velocity in km
y = 4x + 39......slope = 4.....y int = (0,39)....x int is (- 9.75,0) or -9 3/4 for graphing purposes)....so start at (-9.75,0)...and since the slope is 4, go up 4 and to the right 1....plot that...then up 4 and to the right 1...plot that...u will cross the y axis at (0,39)....and just connect ur plotted points and u have ur line......or what u can do since it is asking for the first 6 hrs....sub in 1 for x and solve for y....then sub in 2 for x and solve for y...keep doing this up till 6 and u will have ur line up till 6 hrs
