The program that checks the BMI of a patient is given below:
<h3>THE CODE</h3>
#include <iomanip>
#include <iostream>
#include <math.h>
using namespace std;
// C++ program to illustrate
// how to calculate BMI
float BMI(float height, float weight)
{
float bmi = weight / pow(height, 2);
return bmi;
}
int main()
{
float height = 1.79832;
float weight = 70;
// Function call
float bmi = BMI(height, weight);
cout << "The BMI is " << setprecision(15) << bmi
<< " so ";
// Conditions to find out BMI category
if (bmi < 18.5)
cout << "underweight";
else if (bmi >= 18.5 && bmi < 24.9)
cout << "Healthy";
else if (bmi >= 24.9 && bmi < 30)
cout << "overweight";
else if (bmi >= 30)
cout << "Suffering from Obesity";
return 0;
}
// This code is contributed by aarohirai2616.
<h3>Output: </h3>
The BMI is 21.64532402096181 so Healthy
Read more about algorithms here:
brainly.com/question/24953880
#SPJ1
Answer:
Answer: C Scrum
Explanation:
Answer: C Scrum would BEST support this objective, to collect and evaluate user stories related to the organization’s internally designed CRM tool.
integer userInput
integer i
integer mid
integer array(20) number
userInput = 1
for i = 0; userInput >= 0; i = i + 1
if number[i] > -1
userInput = Get next input
number[i] = userInput
i = i - 1
mid = i / 2
if i > 9
Put "Too many inputs" to output
elseif i % 2 == 0
Put number[mid - 1] to output
else
Put number[mid] to output
Answer:
Net force = 20 N
Explanation:
Given that,
Force acting on the left = 10 N
Force acting on the right = 30 N
Let right side is positive and left side is negative. Let the net force acting on the box is F. So,
F = -10+30
F = 20 N
So, the net force on the box is 20 N and it is in right side.
