A gigantic 25.6 ft. anaconda was seen in a cave by workers at a construction site in Brazil.

Rachel worked 2.5 hours on Monday, 3.5 hours on Tuesday, 2 hours on Thursday, and 5 hours on Saturday. She is paid $10.66 per ho

Agata [3.3K]

Answer:

$138.58

Step-by-step explanation:

You would first set up an equation. You want to know how much money Rachel earned that week, so let's refer to that by using variable t for total money earned this week.

Next, we also know that Rachel is paid 10.66 per hour, so we'll be multiplying it by the number of hours she worked this week. This allows us to set our equation up as follows:

10.66(2.5+3.5+2+5) = t

You would now add like terms.

10.66(13) = t

You would now multiply 10.66 and 13(total number of hours worked this week).

This would get us 138.58, or the total numnber of money Rachel earned this week.

6 0

3 years ago

Which linear function represents the line given by the point-slope equation y +7=(x + 6)?

tiny-mole [99]

Answer:

O f(x) = -x-1

Step-by-step explanation:

We want to isolate the 'y' variable, so we will subtract 7 from both sides.

y = x + 6 - 7

y = x -1

6 0

3 years ago

Sarah is a computer engineer and manager and works for a software company. She receives a

daser333 [38]

Answer:

a) Number of projects in the first year = 90

b) Earnings in the twelfth year = $116500

Total money earned in 12 years = $969000

Step-by-step explanation:

Given that:

Number of projects done in fourth year = 129

Number of projects done in tenth year = 207

There is a fixed increase every year.

a) To find:

Number of projects done in the first year.

This problem is nothing but a case of arithmetic progression.

Let the first term i.e. number of projects done in first year = $a$

Given that:

$a_4=129\\a_{10}=207$

Formula for $n^{th}$ term of an Arithmetic Progression is given as:

$a_n=a+(n-1)d$

Where $d$ will represent the number of projects increased every year.

and $n$ is the year number.

$a_4=129=a+(4-1)d \\\Rightarrow 129=a+3d .....(1)\\a_{10}=207=a+(10-1)d \\\Rightarrow 207=a+9d .....(2)$

Subtracting (2) from (1):

$78 = 6d\\\Rightarrow d =13$

By equation (1):

$129 =a+3\times 13\\\Rightarrow a =129-39\\\Rightarrow a =90$

Number of projects in the first year = 90

b)

Number of projects in the twelfth year =

$a_{12} = a+11d\\\Rightarrow a_{12} = 90+11\times 13 =233$

Each project pays $500

Earnings in the twelfth year = 233 $\times$ 500 = $116500

Sum of an AP is given as:

$S_n=\dfrac{n}{2}(2a+(n-1)d)\\\Rightarrow S_{12}=\dfrac{12}{2}(2\times 90+(12-1)\times 13)\\\Rightarrow S_{12}=6\times 323\\\Rightarrow S_{12}=1938$

It gives us the total number of projects done in 12 years = 1938

Total money earned in 12 years = 500 $\times$ 1938 = $969000

8 0

2 years ago

Grade 8 math question plz show work

Nimfa-mama [501]

A. The population would be 120

You would find 20 percent of 100
To do that, you do 100× 0.2 and add that to 100

B. The population doubles

10×2= 20
20×2= 40, not 30

hope this helps!

6 0

3 years ago

Mistaken giving brainliest!!! Tho

vitfil [10]

Answer:

its C

Step-by-step explanation:

;););)

8 0

3 years ago

Read 2 more answers