3 years ago

In triangle ABC, what is the measure of angle C if A = 85°, a = 35, and c = 25?

2 answers:

yan [13]3 years ago

5 0

Do you have a formula sheet or was one provided to you

3 0

The answer would be (8+7z)/5

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liraira [26]

2x + 7y + 3x - 4y

Collect all the like terms:

2x + 3x = 5x

7y - 4y = 3y

And you end up with 5x + 3y as your final answer :)

8 0

3 years ago

True [87]

X = -6/29 is the correct answer

5 0

3 years ago

shutvik [7]

Subtract 2/3 from both sides.

8 0

3 years ago

AVprozaik [17]

Answer:

$\sqrt{37}$ units

Step-by-step explanation:

If we draw a perpendicular from point (6,2) on the line 6x - y = - 3, then we have to find the length of the perpendicular.

We know the formula of length of perpendicular from a point $(x_{1}, y_{1} )$ to the straight line ax + by + c = 0 is given by

$\frac{|ax_{1} + by_{1} +c |}{\sqrt{a^{2}+b^{2}}}$

Therefore, in our case the perpendicular distance is

$\frac{|6(6)-2+3|}{\sqrt{6^{2} +(-1)^{2} } } = \frac{37}{\sqrt{37} } = \sqrt{37}$ units. (Answer)

6 0

3 years ago

Step2247 [10]

Answer:

Step-by-step explanation:

If the angle is greater than 360°, subtract 360° until the angle is less than 360°

3 0

2 years ago