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Lera25 [3.4K]
3 years ago
15

One number is three less than a second number. Six times the first is 6 more than 3 times the second. Find the numbers.

Mathematics
1 answer:
Karolina [17]3 years ago
4 0

Step-by-step explanation:

Given,

x = y - 3

Also,

6(y - 3) = 3y + 6

6y - 18 = 3y + 6

6y - 3y = 6 + 18

3y = 24

y = 24/3

y = 8

x = 8 - 3

x = 5

Therefore, the first number is 5 and the second number is 8.

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If the maximum value of y=-3x² + mx + 10 is 37, find the values of m.​
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Step-by-step explanation:

y = -3x² + mx + 10

dy/dx = -6x + m.

When dy/dx = 0, -6x + m = 0. => x = m/6.

We have y = -3(m/6)² + m(m/6) + 10 = 37.

=> -m²/12 + m²/6 = 27

=> -m² + 2m² = 324

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Answer:

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