Answer:
see below
Step-by-step explanation:
You distribute the four
so 4x-p
then 4x-6
4x-p= -4p
4x-6=-24
-4p-24 is your answer
Answer:
1) 47/54 probability that the selected person is someone who was not ticketed, given it is a woman.
2) 8/41 probability that the selected person is someone who was not ticketed, given it is a man.
Step-by-step explanation:
A probability is the number of desired outcomes divided by the number of total outcomes.
1. What is the probability that the selected person is someone who was not ticketed, given it is a woman?
7 + 47 = 54 total woman
47 were not ticketed. So
![p = \frac{47}{54}](https://tex.z-dn.net/?f=p%20%3D%20%5Cfrac%7B47%7D%7B54%7D)
47/54 probability that the selected person is someone who was not ticketed, given it is a woman.
2. What is the probability that the selected person is someone who was not ticketed, given it is a man?
33 + 8 = 41 men.
8 were not ticketed. So
![p = \frac{8}{41}](https://tex.z-dn.net/?f=p%20%3D%20%5Cfrac%7B8%7D%7B41%7D)
8/41 probability that the selected person is someone who was not ticketed, given it is a man.
The correlation is positive, negative and no correlation.
Answer:
![0.06](https://tex.z-dn.net/?f=0.06)
Step-by-step explanation:
we know that
The probability of an event is the ratio of the size of the event space to the size of the sample space.
The size of the sample space is the total number of possible outcomes
The event space is the number of outcomes in the event you are interested in.
Let
x------> size of the event space
y-----> size of the sample space
so
![P=\frac{x}{y}](https://tex.z-dn.net/?f=P%3D%5Cfrac%7Bx%7D%7By%7D)
step 1
Find the probability that a point chosen randomly inside the rectangle is in the circle
<em>Find the area of the rectangle</em>
![A=26.2*13=340.6\ in^{2}](https://tex.z-dn.net/?f=A%3D26.2%2A13%3D340.6%5C%20in%5E%7B2%7D)
<em>Find the area of the circle</em>
![A=3.14*(2)^{2} =12.56\ in^{2}](https://tex.z-dn.net/?f=A%3D3.14%2A%282%29%5E%7B2%7D%20%3D12.56%5C%20in%5E%7B2%7D)
In this problem we have
![x=12.56\ in^{2}\\ y=340.6\ in^{2}](https://tex.z-dn.net/?f=x%3D12.56%5C%20in%5E%7B2%7D%5C%5C%20y%3D340.6%5C%20in%5E%7B2%7D)
substitute
![P=\frac{12.56}{340.6}=0.037](https://tex.z-dn.net/?f=P%3D%5Cfrac%7B12.56%7D%7B340.6%7D%3D0.037)
step 2
Find the probability that a point chosen randomly inside the rectangle is in the regular hexagon
<em>Find the area of the regular hexagon</em>
![A=6[\frac{1}{2} (1.8)^{2}sin(60)]=8.42\ in^{2}](https://tex.z-dn.net/?f=A%3D6%5B%5Cfrac%7B1%7D%7B2%7D%20%281.8%29%5E%7B2%7Dsin%2860%29%5D%3D8.42%5C%20in%5E%7B2%7D)
In this problem we have
![x=8.42\ in^{2}\\ y=340.6\ in^{2}](https://tex.z-dn.net/?f=x%3D8.42%5C%20in%5E%7B2%7D%5C%5C%20y%3D340.6%5C%20in%5E%7B2%7D)
substitute
![P=\frac{8.42}{340.6}=0.025](https://tex.z-dn.net/?f=P%3D%5Cfrac%7B8.42%7D%7B340.6%7D%3D0.025)
step 3
Find the probability that a point chosen randomly inside the rectangle is either in the circle or in the regular hexagon
Is the sum of the two probabilities
![0.037+0.025=0.062](https://tex.z-dn.net/?f=0.037%2B0.025%3D0.062)
Round to the nearest hundredth
![0.062=0.06](https://tex.z-dn.net/?f=0.062%3D0.06)
It would be D because both are positive and are square roots