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I am Lyosha [343]
3 years ago
10

Find Y. Round to the nearest tenth. Z 8 ft 17 ft Х Y 16 ft Y= [?]°

Mathematics
1 answer:
mario62 [17]3 years ago
8 0

Answer:

Y = 27.8°

Step-by-step explanation:

Apply the Law of Cosines which is given as c² = a² + b² - 2ab*Cos C

Where,

c = 8

a = 17

b = 16

C = Y

Plug in the values

8² = 17² + 16² - 2*17*16*Cos Y

64 = 545 - 544*Cos Y

64 - 545 = -544*Cos Y

-481 = -544*Cos Y

Divide both sides by -544

-481/-544 = Cos Y

0.884191176 = Cos Y

Y = cos^{-1}(0.884191176)

Y = 27.8478491° ≈ 27.8° (nearest tenth)

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Solve the quadratic function by completing the square. <br> –32 = 2(x2 + 10x)
inna [77]

Answer:

Step-by-step explanation:

x = -2

x = -8

3 0
3 years ago
Circle A has been enlarged to create circle A'. The table below shows the circumference of both circles.
stich3 [128]

Answer:

Option (2) 1.5

Step-by-step explanation:

Rule for the dilation of an image by a scale factor is,

Scale factor = \frac{\text{Radius of image circle A'}}{\text{Radius of pre-image A}}=\frac{r'}{r}

                    = \frac{(2\pi) r'}{(2\pi) r}

                    = \frac{\text{Circumference of image}}{\text{Circumference of pre-image}}

                    = \frac{10.5}{7}

                    = 1.5

Therefore, scale factor was used to create a circle A' = 1.5

Option (2) will be the correct option.

8 0
3 years ago
Find the LCD of the rational expression<br> Problems 3,4,5<br> Please help!!!
horrorfan [7]

The LCD of the rational expressions are 30x^5, (3x - 1)(x + 6) and (x + 3)(x + 5)^2

<h3>How to determine the LCD of the rational expressions?</h3>

<u>Expression 1</u>

The rational expressions are given as:

3/10x^2 and x + 7/15x^5

Write out the denominators

10x^2 and /15x^5

Expand each of the denominator.

10x^2 = 2 * 5 * x * x

15x^5 = 3 * 5 * x* x * x * x * x

Multiply all common factors without repetition

So, the LCD of the denominators are

LCD = 2 * 3 * 5 * x* x * x * x * x

Evaluate

LCD = 30x^5

<u>Expression 2</u>

The rational expressions are given as:

9/3x - 1 and 2x/x + 6

Write out the denominators

3x - 1 and x + 6

Expand each of the denominator.

10x^2 = 3x - 1

15x^5 = x + 6

Multiply all common factors without repetition

So, the LCD of the denominators are

LCD = (3x - 1)(x + 6)

<u>Expression 3</u>

The rational expressions are given as:

8x/(x + 5)^2 and 4x + 1/x^2 + 8x + 15

Write out the denominators

(x + 5)^2 and x^2 + 8x + 15

Expand each of the denominator.

(x + 5)^2 = (x + 5) * (x + 5)

x^2 + 8x + 15 = (x + 3) * (x + 5)

Multiply all common factors without repetition

So, the LCD of the denominators are

LCD = (x + 3) * (x + 5) * (x + 5)

LCD = (x + 3)(x + 5)^2

Hence, the LCD of the rational expressions are 30x^5, (3x - 1)(x + 6) and (x + 3)(x + 5)^2

Read more about LCD at:

brainly.com/question/1025735

#SPJ1

8 0
2 years ago
Find a solution to the initial value problem,<br> y″+12x=0, y(0)=2,y′(0)=−1.
levacccp [35]

Answer:

y = -2*x^3 - x + 2

Step-by-step explanation:

We want to solve the differential equation:

y'' + 12*x = 0

such that:

y(0) = 2

y'(0) = -1

We can rewrite our equation to:

y'' = -12x

if we integrate at both sides, we get:

\int {y''} \, dx  = y'=  \int {-12x} \, dx

Solving that integral we can find the value of y', so we will get:

y' = -12* (1/2)*x^2 + C = -6*x^2 + C

where C is the constant of integration.

Evaluating y' in x = 0 we get:

y'(0) = -6*0^2 + C = C

and for the initial value problem, we know that:

y'(0) = -1

then:

y'(0) = -1 = C

C = -1

So we have the equation:

y' = -6*x^2 - 1

Now we can integrate again, to get:

y = -6*(1/3)*x^3 - 1*x + K

y =  -2*x^3 - x + K

Where K is the constant of integration.

Evaluating or function in x = 0 we get:

y(0) = -2*0^3 - 0 + K

y(0) = K

And by the initial value, we know that: y(0) = 2

Then:

y(0) = 2 = K

K = 2

The function is:

y = -2*x^3 - x + 2

4 0
3 years ago
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