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V125BC [204]
3 years ago
15

What are two different systems of equations with (1, -2) as the solution?

Mathematics
1 answer:
Virty [35]3 years ago
5 0

Answer:

give me brainlist

Step-by-step explanation:

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Answer:

In the photo below.

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Simplify <br><img src="https://tex.z-dn.net/?f=4%20%2B%20%20%5Cfrac%7B3%7D%7B7%7Dx%20-%202%20-%20%20%5Cfrac%7B2%7D%7B7%7Dx%20%20
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4 + \frac{3}{7}x - 2 - \frac{2}{7}x\\\\\text{combine like terms}\\\\\left(\dfrac{3}{7}x-\dfrac{2}{7}x\right)+(4-2)=\dfrac{3-2}{7}x+2=\boxed{\dfrac{1}{7}x+2}

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3 years ago
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Help on this 3 questions pleaseeeee!!!!
ra1l [238]

Answer:

14. D

15. A

16. A

Step-by-step explanation:

14. Point slope form formula: y-y₁=m(x-x₁).

When graphing you always want to think x/y for your slope.

X-axis increases by 2 and the Y-axis increases by 10, which would make the slope (m) 2/10 = 1/5.

If your slope is does not come out correct, then you can prove your point.

15. The given information is (-2,2): m=-1.

Given the Point slope formula: y-y₁=m(x-x₁), you can replace m to -1, y₁=2 and x=+2. (Two negatives would make a positive.)

Your answer: y-2=-(x+2)

16. Given: y=4x-7; (3,0)

Parallels lines: Same slope different y-intercepts.

A and D has the same slope and different y-interecepts, but your answer would be A because the equation that was given as a negative y-intercepts.

6 0
3 years ago
Liam is setting up folding chairs for a meeting. If he arranges the chairs in 4 rows of the same length, he has 9 chairs left ov
Charra [1.4K]
The answer is 32, depending on how you do the math will be different outcomes
5 0
3 years ago
Help me with differentation and integration please!!
Marina86 [1]

Answer:

See below

Step-by-step explanation:

\dfrac{d}{dx} (\tan^3 x) = 3\sec^4 x - 3\sec^2 x

Recall

\dfrac{d}{dx}\tan x=\sec^2

Using the chain rule

\dfrac{dy}{dx}= \dfrac{dy}{du} \dfrac{du}{dx}

such that u = \tan x

we can get a general formulation for

y = \tan^n x

Considering the power rule

\boxed{\dfrac{d}{dx} x^n = nx^{n-1}}

we have

\dfrac{dy}{dx} =n u^{n-1} \sec^2 x \implies \dfrac{dy}{dx} =n \tan^{n-1} \sec^2 x

therefore,

\dfrac{d}{dx}\tan^3 x=3\tan^2x \sec^2x

Now, once

\sec^2 x - 1= \tan^2x

we have

3\tan^2x \sec^2x =  3(\sec^2 x - 1) \sec^2x = 3\sec^4x-3\sec^2x

Hence, we showed

\dfrac{d}{dx} (\tan^3 x) = 3\sec^4 x - 3\sec^2 x

================================================

For the integration,

$\int \sec^4 x\, dx $

considering the previous part, we will use the identity

\boxed{\sec^2 x - 1= \tan^2x}

thus

$\int\sec^4x\,dx=\int \sec^2 x(\tan^2x+1)\,dx = \int \sec^2 x \tan^2x+\sec^2 x\,dx$

and

$\int \sec^2 x \tan^2x+\sec^2 x\,dx = \int \sec^2 x \tan^2x\,dx + \int \sec^2 x\,dx $

Considering u = \tan x

and then du=\sec^2x\ dx

we have

$\int u^2 \, du = \dfrac{u^3}{3}+C$

Therefore,

$\int \sec^2 x \tan^2x\,dx + \int \sec^2 x\,dx = \dfrac{\tan^3 x}{3}+\tan x + C$

$\boxed{\int \sec^4 x\, dx  = \dfrac{\tan^3 x}{3}+\tan x + C }$

6 0
2 years ago
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