Question

Find the value of x. Round to the nearest tenth.thank you in advance for the help! ​

Answer 1

Answer:

${1.4}^{2} + {x}^{2} = {2.1}^{2} \\ 1.96 + {x}^{2} = 4.41 \\ {x}^{2} = 4.41 - 1.96 \\ {x}^{2} = 2.45 \\ x = \sqrt{2.45} \\ x = 3.12ft$

Step-by-step explanation:

YOU HAVE TO USE THE PYTHAGORAS THEORAM

Answer 2

Answer:

x ≈ 3.1

Step-by-step explanation:

Using Pythagoras' identity in the right triangle with hypotenuse 2.1 and

legs 1.4 and $\frac{1}{2}$ x, thus

($\frac{1}{2}$ x )² + 1.4² = 2.1², that is

$\frac{1}{4}$ x² + 1.96 = 4.41 ( subtract 1.96 from both sides )

$\frac{1}{4}$ x² = 2.45 ( multiply both sides by 4 )

x² = 9.8 ( take the square root of both sides )

x ≈ 3.1 ( to the nearest tenth )