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gavmur [86]
3 years ago
9

What's the circumference of a circle with a diameter of 9 inches? Use 3.14 for n.

Mathematics
1 answer:
Rainbow [258]3 years ago
8 0

Answer:

28.26 in

Step-by-step explanation:

Radius = (1/2) diameter

Radius = (1/2)(9)

Radius = 4.5 in

Circumference = 2πr

Circumference = 2(3.14)(4.5)

Circumference = 28.26 in

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Step-by-step explanation:

first bro + 2nd bro + 3rd bro

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Answer:

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Answer:

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2 years ago
What is the distance between points (-2, 8) and (6, -2)? Round to the nearest tenth of a unit.
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4 0
3 years ago
What sample size is needed to give a margin of error within in estimating a population mean with 95% confidence, assuming a prev
atroni [7]

Answer:

n = (\frac{1.96\sqrt{\pi(1-\pi)}}{M})^2

The sample size needed is n(if a decimal number, round up to the next integer), considering the estimate of the proportion \pi(if no previous estimate use 0.5) and M is the desired margin of error.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of 1 - \frac{\alpha}{2}.

The margin of error is of:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

95% confidence level

So \alpha = 0.05, z is the value of Z that has a p-value of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

Needed sample size:

The needed sample size is n. We have that:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

M = 1.96\sqrt{\frac{\pi(1-\pi)}{n}}

\sqrt{n}M = 1.96\sqrt{\pi(1-\pi)}

\sqrt{n} = \frac{1.96\sqrt{\pi(1-\pi)}}{M}

(\sqrt{n})^2 = (\frac{1.96\sqrt{\pi(1-\pi)}}{M})^2

n = (\frac{1.96\sqrt{\pi(1-\pi)}}{M})^2

The sample size needed is n(if a decimal number, round up to the next integer), considering the estimate of the proportion \pi(if no previous estimate use 0.5) and M is the desired margin of error.

4 0
3 years ago
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