All categories

2 years ago

Help!!! evaluate peicewise functions

Mathematics

1 answer:

aksik [14]2 years ago

4 0

Answer:

Step-by-step explanation:

You choose the middle one because 3<(4)<10 makes sense where as the other ones don't when you plug in 4. Then you solve the equation which is x^2-7 and then you get 16-7 which is 9.

You might be interested in

What are the polar coordinates for (-7, 7)?

scZoUnD [109]

Answer:

The polar form of (7, - 7) is (r, θ) = (7√2, - π/4)

Step-by-step explanation:

3 0

3 years ago

PLEASE HELP! GIVING BRAINLIEST!

jeyben [28]

Answer:

The answer is A

Step-by-step explanation:

7 0

3 years ago

F(x)=5x-2 find the slope of f

Inessa [10]

Answer:

Slope = 5

Step-by-step explanation:

Standard slope intercept form: y = mx + b

where m = slope of the function

so m = 5

Hope this helps!

7 0

3 years ago

[DUE TOMORROW] What is the area, in square decimeters, of a right

Ilia_Sergeevich [38]

Answer:

120

Step-by-step explanation:

since 26 is the longest side, it would be the hypotenus and we can exclude it.

the equation for the area of a triangle is basexheight/2.

our base or height must be the other two sides

10x24=240

240/2=120

so 120 would be ur answer

5 0

3 years ago

The vertices of triangle ABC are A(−5, 1), B(−2.5, 7), and C(0, 1). Find the new coordinates of the vertices after the given tra

dybincka [34]

Answer:

Step-by-step explanation:

The vertices of triangle ABC are A(−5, 1), B(−2.5, 7), and C(0, 1).

The given translation of vertices,

This translation shows shift x-coordinate 3 unit right and y-coordinate 1 unit down.

First translate vertices A(-5,1)

$A(-5,1)\rightarrow A'(-5+3,1-1)$

New vertices A'(-2,0)

Now vertices B(-2.5,7)

$B(-2.5,7)\rightarrow B'(-2.5+3,7-1)$

New vertices B'(0.5,6)

Now vertices C(0,1)

$C(0,1)\rightarrow C'(0+3,1-1)$

New vertices C'(3,0)

Hence, the new coordinate of the vertices are A'(-2,0) , B'(0.5,6) and C'(3,0)

4 0

3 years ago