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4 years ago

What is the answer key to GO MATH 6grade page 393

Mathematics

1 answer:

Lina20 [59]4 years ago

7 0

Answer:

This website is not an answer key website. You ask a question and we respond. Write your question and ill reply. Thanks for the points.

Step-by-step explanation:

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A parallelogram has one angle that measures 140 degrees. What are the measures of the other three angles in the parallelogram?

sweet [91]

...............................

6 0

3 years ago

A high percentage of people who fracture or dislocate a bone see a doctor for that condition. Suppose the percentage is 99%. Con

marishachu [46]

Answer:

(i) 0.15708

(ii) 0.432488

(iii) 3

Step-by-step explanation:

Given that, 99% of people who fracture or dislocate a bone see a doctor for that condition.

There is only two chance either the person having fracture or dislocation of bone will either see the doctor or not.

As per previous data, if one person got a fracture or dislocation of bone, the chance of seeing the doctor is 0.99. Assuming this chance is the same for every individual, so the total number of people having fractured or dislocated a bone can be considered as Bernoulli's population.

Let p be the probability of success represented by the chances of not seeing a doctor by any one individual having fractured or dislocated a bone.

So, p=1-0.99=0.01

According to Bernoulli's theorem, the probability of exactly r success among the total of n randomly selected from Bernoulli's population is

$P(r)=\binom{n}{r}p^r(1-p)^{n-r}\cdots(i)$

(i) The total number of persons randomly selected, n=400.

The probability that exactly 5 of them did not see a doctor

So, r=5 , p=0.01

Using equation (i),

$P(r=5)=\binom{400}{5}(0.01)^5(1-0.01)^{400-5}$

$=\frac{400!}{(400-5)!\times 5!}(0.01)^5(0.99)^{395}$

=0.15708

(ii) The probability that fewer than four of them did not see a doctor

$=P(r$

$=P(r=0)+P(r=1)+P(r=2)+P(r=3)$

$=\binom{400}{0}(0.01)^0(0.99)^{400}+\binom{400}{1}(0.01)^1(0.99)^{399}+\binom{400}{2}(0.01)^2(0.99)^{398}+\binom{400}{3}(0.01)^3(0.99)^{397}$

$=0.017951+0.072527+0.146154+0.195856$

$=0.432488$

(iii) The expected number of people who would not see a doctor

$=np$

$=300\times 0.01$

7 0

3 years ago

Find eah missing length to the nearest tenth

olga_2 [115]

Let’s go with 7.0 that is what I think it is

6 0

3 years ago

Please answer correctly !!!!!!!!!! Will mark brainliest !!!!!!!!!!!!

Drupady [299]

Answer:

Step-by-step explanation:

f(6) = -6 this is the value when the x value is 6

g(5) = -5 this is the value when the x value is 5

4 * f(6) -6*g(5)

4*-6 - 6* -5

-24 + 30

5 0

3 years ago

Read 2 more answers

Please help with these partial fractions!!!

VARVARA [1.3K]

a. Factorize the denominator:

$\dfrac{x+14}{x^2-2x-8}=\dfrac{x+14}{(x-4)(x+2)}$

Then we're looking for $a,b$ such that

$\dfrac{x+14}{x^2-2x-8}=\dfrac a{x-4}+\dfrac b{x+2}$

$\implies x+14=a(x+2)+b(x-4)$

If $x=4$ , then $18=6a\implies a=3$ ; if $x=-2$ , then $12=-6b\implies b=-2$ . So we have

$\dfrac{x+14}{x^2-2x-8}=\dfrac3{x-4}-\dfrac2{x+2}$

as required.

b. Same setup as in (a):

$\dfrac{-3x^2+5x+6}{x^3+x^2}=\dfrac{-3x^2+5x+6}{x^2(x+1)}$

We want to find $a,b,c$ such that

$\dfrac{-3x^2+5x+6}{x^2(x+1)}=\dfrac ax+\dfrac b{x^2}+\dfrac c{x+1}$

Quick aside: for the second term, since the denominator has degree 2, we should be looking for another constant $b'$ such that the numerator of the second term is $b'x+b$ . We always want the polynomial in the numerator to have degree 1 less than the degree of the denominator. But we would end up determining $b'=0$ anyway.