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Mrac [35]
3 years ago
13

Write an equation and solve. Round to the nearest hundredth where necessary.

Mathematics
2 answers:
xenn [34]3 years ago
6 0

The answer is 8 divided by 3.000 =0.375

sasho [114]3 years ago
3 0

Answer:

A

Step-by-step explanation:

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PLEASE HELP 25 POINTS!!
iris [78.8K]

Answer:

m= masters degree salary and b=bachelors degree salary.

m = 2b - 45000

m + b = 112000

Substitute to get

2b - 45000 + b = 112000

3b = 156000

b = 52000

So m = 59000

Check to see if these numbers work

59000 = 2*52000 - 45000 true

59000 + 52000 = 112000 true

Step-by-step explanation:

7 0
3 years ago
At a clearance sale,Jill got 70% off a silver bracelet.If she paid the cashier $27 ,what was the original price of the bracelet​
mart [117]

Answer:

$38.57

Step-by-step explanation:

Make a proportion.

\frac{27}{x} = \frac{70}{100}

Cross multiply.

27 times 100 = 2700

2700 divided by 70 = 38.57142857

Round the result to the hundredths place.

38.57142857 ≈ 38.57

**Hope this helps!

4 0
3 years ago
For what is the value of the rational expression below? X+20/x+4
Rus_ich [418]

Answer:

(4 + 20) / (4 + 4)  

= 24 / 8  

= 3

5 0
3 years ago
Which function has no horizontal asymptote? F (x) = StartFraction 2 x minus 1 Over 3 x squared EndFraction f (x) = StartFraction
yanalaym [24]

Answer:

f(x)=\frac{2x^2}{3x-1}

Step-by-step explanation:

The function  f(x)=\frac{2x-1}{3x} has a horizontal asymptote which is y=\frac{2}{3}

The function  f(x)=\frac{x-1}{3x} has a horizontal asymptote which is y=\frac{1}{3}

The function  f(x)=\frac{2x^2}{3x-1} has no horizontal asymptote  because the numerator has a degree which is higher than the degree of the denominator,

The function  f(x)=\frac{3x^2}{x^2-1} has a horizontal asymptote which is y=3

3 0
3 years ago
Read 2 more answers
I need help with Question 14 . I need to submit it by monday...<br> Pls help
GaryK [48]

Answer:

Distance between A and B is 5400 meters

Step-by-step explanation:

Consider "D" the letter to identify distance between A and B

Let's use "t" to identify the time of the first encounter (Devi and Kumar), and create an equation that states that the distance covered by Devi (at 100 m/min) in time "t", is equal to the total distance D minus what Kumar has covered at his speed (80 m/min) in that same time:

Recall that distance equals the speed  times the time:

distance= speed * time

First encounter:

100 * t = D - 80 * t

180 * t = D    Equation (1)

Not, 6 minutes later (at time t+6) , Devi and Li Ting meet .

Then for this encounter the distance covered by Devi equals total distance d minus the distance covered by Li Ting:

100 *(t+6) = D - 75 * (t+6)

100 t + 600 = D - 75 t - 450

175 T + 150 = D    Equation (2)

Now, let's equal equation (1) to equation (2), since D should be the same:

180 t = 175 t + 150

5 t = 150

t = 30

Then the time t (first encounter) is 30 minutes. Knowing this, we can use either equation to find D:

From Equation (1) for example: D = 180 * t = 180 * 30 = 5400 meters

5 0
4 years ago
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