2p = 396/63 (= 6.2857)
p = 198/63 (= 3.14)
I'm not really sure but I know that the answer is <u>definitely not</u> 0.25 or 0.5.
Answer:
Class width = 20
Approximate lower class limit of the first class = 110
Approximate Upper class limit of the first class = 119
Step-by-step Explanation:
The class width of the histogram attached below can be gotten by finding the difference between successive lower class limits.
Thus, class width = 130 - 110 = 20
The approximate lower class limit of the first class is the lowest score we have in the first class = 110
The approximate upper class limit of the first class is the closest highest score that fall within the first class and is below the lower limit of the second class. Thus approximate upper class limit of the first class = 129
All you need to do is use the formula to solve. What I do is I plug in the information that I know, and then I just solve. In this case it would be:
V= (4)
- pie(3.14)*4.8(cubed)
3
I hope I was a good help, and if you still need help, come to my page and ask the question on specifically what you need help with. :D
Answer:
D) A quadrilateral with one pair of opposite sides parallel
Step-by-step explanation:
Choice D matches the description of a trapezoid, not a parallelogram. That description will not guarantee the figure is a parallelogram.