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ivanzaharov [21]
2 years ago
15

Can anyone help? I’ll make sure to give Brainly :) thank you sm !

Mathematics
2 answers:
ale4655 [162]2 years ago
4 0

Answers:

  • first blank = 0
  • second blank = 1
  • third blank = 0

So basically the two solutions are (-2, 0) and (1, 0)

=============================================

Explanation:

In this context, the term "solution" is another word for "x intercept". Also, the term "root" is the same as "x intercept". We have three ways to say the same thing.

The blue graph crosses the x axis at the locations (-2,0) and (1,0); therefore, these are the roots. We can say that x = -2 and x = 1 are the roots as shorthand.

Side note: This is assuming the blue curve crosses the x axis at the midpoint between x = 0 and x = 2.

Nuetrik [128]2 years ago
3 0

Answer:

Is this the full question?

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Explain tge distace formula. then use it to calculate the distance between A(1,1) and B(7,-7).
Juliette [100K]
The distance formula is based on the Pythagorean Theorem:

Distance = Square Root [(X2 - X1)^2<span> + (Y2 - Y1)^</span>2<span>]
</span>Distance = Square Root [(7 -1)^2 + (-7 -1)^2]
Distance = Square Root [ 6^2 + -8^2]Distance = Square Root [ 36 + 64 ]Distance = Square Root [100 ]Distance = 10
Source:http://www.1728.org/distance.htm

5 0
3 years ago
1. Explain why n root a^n= |a| when n is even, but not when n is odd.
kogti [31]

Step-by-step explanation:

In the expression a^n, for integer values of n greater than 1, there are n factors. For example, a^2 = a * 2 (2 factors), a^3 = a * a * a (3 factors), etc.

For a non-negative value of a, a^n is non-negative for all values of n.

If a is negative, and n is even, then a^n is non-negative.

If a is negative, and n is odd, then a^n is negative.

|a| is non-negative for all values of a.

sqrt_n(a^n) is negative for negative a and odd n, but |a| is always non-negative, so sqrtn(a^n) cannot equal |a| for odd n.

8 0
3 years ago
Nathan bought a pair of boots for $79.95 and 2 shirts for $19.99 each. The sales tax is 7.5%. How much did Nathan pay for all th
kodGreya [7K]
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5 0
2 years ago
Kelly needs to order lunch for orders 6 people at a business meeting. Her menu choices are chicken salad for a cost of $5 per pe
nirvana33 [79]
Ok , with that information we can write the equations
x + y = 6
5x + 4y = 28

Where x = how many people ordered chicken
and y = how many people ordered egg salad

Through elimination , we can set one of the variables in both equations equal so we can eliminate it :

(4)x + (4)y = (4)6
5x + 4y = 28

4x + 4y = 24. equation 1
5x + 4y = 28. equation 2

Now we can subtract the second equation by the first equation and isolate one variable:
equation 2 - equation 1

5x - 4x + 4y - 4y = 28 - 24

x = 4

Now that we discovered our x value ( How many people ordered chicken salad ) , we can apply it to one of the equations and discover y ( how many people ordered egg salad)

x + y = 6
x= 4
4 + y = 6

We can shift 4 to the other side of the equation by subtracting 4 from both sides of the equation:
4 - 4 + y = 6 - 4
y = 2

x=4 and y=2

So the awnser is :
4 people ordered chicken salad and 2 people ordered egg salad!

I hope you understood my brief explanation!!

p.s if you want to know how to use another method to solve these problems ( Substition) , just let me know in a comentary down here
5 0
2 years ago
What is the midpoint of the segment shown below?
Burka [1]

Answer:

choice. c.) (5, 1/2)

Step-by-step explanation:

(5, 4) and (5, -3)

Use midpoint formula  ( (a + x)/2 , (b + y)/2)  for (a,b), (x,y)

midpoint = ( (5+5)/2, (4+- 3)/2) = (5, 1/2)  

5 0
3 years ago
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