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Luden [163]
3 years ago
9

I will mark as brainliest but I need the answer for these 2 questions

Mathematics
1 answer:
KATRIN_1 [288]3 years ago
4 0

1.6

2.24

Step-by-step explanation:

1.it's the same distance from the middle

2.64-12=52

76-52=24

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Drag the point A to the location indicated in each scenario to complete each statement.
Art [367]

The graph from which the position of the point <em>A</em> can determined following

the multiplication with a scalar is attached.

Responses:

  • If <em>A</em> is in quadrant I and is multiplied by a negative scalar, <em>c</em>, then c·A is in <u>quadrant III</u>
  • If A is in quadrant II and is multiplied by a positive scalar, <em>c</em>, then c·A is in <u>quadrant II</u>
  • If <em>A</em> is in quadrant II and is multiplied by a negative scalar, <em>c</em>, then c·A is in <u>quadrant IV</u>
  • If <em>A</em> is in quadrant III and is multiplied by a negative scalar, <em>c</em>, then c·A is in <u>quadrant I</u>

<h3>Methods by which the above responses are obtained</h3>

Background information;

The question relates to the coordinate system with the abscissa represent the real number and the ordinate representing the imaginary number.

Solution:

If A is in quadrant I; A = a + b·i

When multiplied by a negative scalar, <em>c</em>, we get;

c·A = c·a + c·b·i

Therefore;

c·a is negative

c·b is negative

  • c·A = c·a + c·b·i is in the <u>quadrant III</u> (third quadrant)

If A is quadrant II, we have;

A = -a + b·i

When multiplied by a positive scalar <em>c</em>, we have;

c·A = c·(-a) + c·b·i = -c·a + c·b·i

-c·a is negative

c·b·i is positive

Therefore;

  • c·A = -c·a + c·b·i is in <u>quadrant II</u>

Multiplying <em>A</em> by negative scalar if <em>A</em> is in quadrant II, we have;

c·A = -c·a + c·b·i

-c·a is positive

c·b·i is negative

Therefore;

c·A = -c·a + c·b·i is in <u>quadrant IV</u>

If A is in quadrant III, we have;

A = a + b·i

a is negative

b is negative

Multiplying <em>A</em> with a negative scalar <em>c</em> gives;

c·A = c·a + c·b·i

c·a is positive

c·b  is positive

Therefore;

  • c·A = c·a + c·b·i is in<u> quadrant I</u>

Learn more about real and imaginary numbers here;

brainly.com/question/5082885

brainly.com/question/13573157

4 0
3 years ago
I need help please?<br><br><br>​
ludmilkaskok [199]

Answer:

B

Step-by-step explanation:

the blue parabola shows (1/4x)^2, the red shoes x^2, you can see the horizontal stretch, hope this helps :)

Download pdf
7 0
3 years ago
BRAINLIEST ASAP! PLEASE. HELP ME :) I need help with part 2 of the question.
tino4ka555 [31]

Part 2:

-4a + 2 + 11a = 5a + 3 + 2a

~Combine like terms

7a + 2 = 7a + 3

~Subtract 2 to both sides

7a = 7a - 1

~Subtract 7a to both sides

0 = 1

Therefore, there are no solutions.

Best of Luck!

3 0
3 years ago
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Mark spent 5/12 of an hour on his math homework and 6/12 of and hour on english homework altogether,what fraction of an hour did
Nastasia [14]
Mark spent 11/12 of an hour doing both math and english homework
8 0
3 years ago
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If middle school and senior school are winning football games in the ratio 3:9 . If the Middle school won 17 games, calculate ho
Helen [10]
The Middle school won 17 games so the senior school won 51 games

4 0
3 years ago
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