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2 years ago

Can u please help me??

Mathematics

1 answer:

frez [133]2 years ago

3 0

Answer:

Given GP:

tₙ = (1/3)ⁿ⁻¹

We see that:

t₁ = 1, r = 1/3

Sum of n terms:

Sₙ = t₁(1 - rⁿ)/(1 - r)
Sₙ = [1 - (1/3)ⁿ] / (1 - 1/3) = [1 - (1/3)ⁿ] / (2/3) = 3/2 [1 - (1/3)ⁿ]
Sₙ = 3/2 [1 - (1/3)ⁿ]

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3 years ago

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What is the area of the regular pentagon below?

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