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2 years ago

Can u please help me??

Mathematics

1 answer:

frez [133]2 years ago

3 0

Answer:

Given GP:

tₙ = (1/3)ⁿ⁻¹

We see that:

t₁ = 1, r = 1/3

Sum of n terms:

Sₙ = t₁(1 - rⁿ)/(1 - r)
Sₙ = [1 - (1/3)ⁿ] / (1 - 1/3) = [1 - (1/3)ⁿ] / (2/3) = 3/2 [1 - (1/3)ⁿ]
Sₙ = 3/2 [1 - (1/3)ⁿ]

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PLEASE ANSWER I WILL GIVE YOU BRAINIEST!!!!!!!!!!!!!!!!!!!!!!

Radda [10]

Answer:

C. x > 15

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

if a motercycle is moving at a constant speed down the highway of 40 km/hr, how long would it the motorcycle to travel 10 km

ahrayia [7]

Answer:

15 minutes

Step-by-step explanation:

First, the motorcycle goes at a speed of 40 km/hr.

The question asks for how long it would take to travel 10 km.

Well, there are 60 minutes in an hour, since we will be translating into minutes.

Also, 10 km is 1/4 of 40 km, so it would make sense that the time length would be 1/4 of an hour as well.

1/4 of 60 minutes is 15 minutes. So it takes 15 minutes for the motorcycle to travel 10 km.

Now, if all this wordy stuff is too much to comprehend, you can also solve using proportional relationships.

$\frac{40km}{60min}=\frac{10km}{xmin}$

Now cross multiply:

$40km*xmin=10km*60min\\40x=600$

Divide both sides by 40:

$\frac{40x}{40}=\frac{600}{40}\\x=15$

Again, this shows that it wouls take 15 minutes for the motorcycle to travel 10 km.

6 0

3 years ago

20 points, please help

Damm [24]

Answer:

The answer to your question is: 83 + 6 $\sqrt{35}$

Step-by-step explanation:

This is a square of a binomial.

(2 $\sqrt{5}$ + 3 $\sqrt{7} )^{2}$

1.- Square of the first term

( 2 $\sqrt{5} )^{2}$ = 4(5) = 20

2.- Twice the product of the two terms

(2)(2 $\sqrt{5} )$ (3 $\sqrt{7} )$ = 6 $\sqrt{35}$

3.- Square of the second term

(3 $\sqrt{7)})^{2}$ = 9(7) = 63

4.- Write the solution

20 + 6 $\sqrt{35}$ + 63

83 + 6 $\sqrt{35}$

7 0

3 years ago

4.3-4.4 section of pre-calculus problem in link please also tell how you got your answer if can .

Tanya [424]

Answer:

the image os not clear mate sorry

7 0

3 years ago

A ball is thrown in the air from a ledge. Its height in feet is represented by

Genrish500 [490]

check the picture below.

$\bf \stackrel{f(x)}{0}=-16(x^2-6x-7)\implies 0=x^2-6x-7 \\\\\\ 0=(x-7)(x+1)\implies x= \begin{cases} \boxed{7}\\ -1 \end{cases}$

it cannot be -1, because is a seconds amount after moving.

8 0

3 years ago