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prisoha [69]
3 years ago
6

Can u please help me??

Mathematics
1 answer:
frez [133]3 years ago
3 0

Answer:

<u>Given GP:</u>

  • tₙ = (1/3)ⁿ⁻¹

<u>We see that:</u>

  • t₁ = 1, r = 1/3

<u>Sum of  n terms:</u>

  • Sₙ = t₁(1 - rⁿ)/(1 - r)
  • Sₙ = [1 - (1/3)ⁿ] / (1 - 1/3) = [1 - (1/3)ⁿ] / (2/3) = 3/2 [1 - (1/3)ⁿ]
  • Sₙ = 3/2 [1 - (1/3)ⁿ]
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3 years ago
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Hey Child.

The answer to this is 1 or 7:

To find the range for the number of measures played to satisfy our solution, we must solve for x using s = 80.

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4 0
4 years ago
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Simora [160]

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What is the square root of x^6 over y^4
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