Question

Can u please help me??

Answer 1

Answer:

Given GP:

• tₙ = (1/3)ⁿ⁻¹

We see that:

• t₁ = 1, r = 1/3

Sum of  n terms:

• Sₙ = t₁(1 - rⁿ)/(1 - r)
• Sₙ = [1 - (1/3)ⁿ] / (1 - 1/3) = [1 - (1/3)ⁿ] / (2/3) = 3/2 [1 - (1/3)ⁿ]
• Sₙ = 3/2 [1 - (1/3)ⁿ]