3 years ago

Twenty-five ten-thousandths in scientific notation?

Mathematics

1 answer:

Marta_Voda [28]3 years ago

6 0

The answer should be 2.5x10^-4

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Find the perimeter of the quadrilateral that has vertices at (8,13), (5,-18), (-6,-6), and (-2,-5).

kodGreya [7K]

Answer:

72.14 units

Step-by-step explanation:

Let A(8,13), B(5,-18),C(-6,-6) and D(-2,-5)

Apply the distance formula as;

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Finding the lengths of the segments

For AB

$AB=\sqrt{(5-8)^2+(-18-13)^2} =\sqrt{(-3^2)+(-31^2)} =\sqrt{970} =31.14$

For BC

$BC=\sqrt{(-6-5)^2+(-6--18)^2} =\sqrt{(-11^2)+12^2} =\sqrt{265} =16.28$

For CD

$CD=\sqrt{(-2--6)^2+(-5--6)^2} =\sqrt{4^2+1^2} =\sqrt{16+1} =\sqrt{17} =4.12$

For DA

$DA=\sqrt{(8--2)^2+(13--5)^2} =\sqrt{10^2+18^2} =\sqrt{424} =20.6$

Finding the perimeter will be;

31.14+16.28+4.12+20.6=72.14 units

3 0

3 years ago

An envelope is 4 cm longer than it is wide. the area is 96 square centimeters. find the length and width.

Dennis_Churaev [7]

So, L*W=A Because it is 4 cm longer, L=W+4 Because the area is 96, LW=96 Substitute to get W(W+4)=96 Multiply it out. W^2+4W-96=0 By solving the quadratic, W+12(W-8)=0 so either W+12 or W-8 is zero. The width must be positive, so the width is 8. Therefore the length is 12.

Hope this helps.

4 0

3 years ago

Find the value of x. 3x +7 D 2x + 7 3x 16

Mashcka [7]

Answer:

sum of interior angle of a triangle is 180 degree

so,

3x +7 + 2x+7 +3x+6 = 180

8x + 20 = 180

8x = 180 - 20

8x = 160

x = 160/ 8