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Viefleur [7K]
3 years ago
14

Given z1 = 1+i and z2 = 2+3i.

Mathematics
1 answer:
Margaret [11]3 years ago
4 0

Answer:

(a) w=2+5i-6=-4+5i

Multiplicative inverse of w will be \frac{1}{-4+5i}

(B) As w is same as the product of z_1\ and\ z_2

So there multiplicative inverse will also be same

Step-by-step explanation:

We have given two complex numbers

z_1=1+i and z_2=3+2i

(a) First we have to find w=z_1z_2

So w=(1+i)(2+3i)=2+3i+2i+6i^2=2+5i+6i^2

As we know that i^2=-1

So w=2+5i-6=-4+5i

Multiplicative inverse :

It is that number when multiply with the number which we have have to find the multiplicative inverse gives result as 1

So multiplicative inverse of w will be \frac{1}{-4+5i}

Because when we multiply -4+5i with \frac{1}{-4+5i} it gives result as 1

(b) As w is same as the product of z_1\ and\ z_2

So there multiplicative inverse will also be same

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The student then emptied the flask and dired it once again. To the empty flask he added pieces of a metal until the flask was bo
spayn [35]

Answer:

The question is incomplete, below is the complete question:

The volume of a flask has been determined to be 26.918 mL, and the mass of the flask has been determined to be 32.634g. The student then emptied the flask and dried it once again. To the empty flask, he added pieces of metal until the flask was about half full. He weighed the stoppered flask containing the metal and found that its mass was 100.356g. Next, he filled the flask containing the metal with water, stoppered it, reweighed it and obtained a total mass of 121.860g.

a.) Find the mass of the metal in the flask. (show work)

b.) Find the mass of water in the flask. (show work)

c.) Find the volume of water in the flask. (show work)

d.) Find the volume of metal in the flask (show work)

e.) Find the density of the metal. (show work)

Answers:

a.  mass of metal in the flask = 67.722g

b. mass of water in the flask = 21.504g

c. volume of water in the flask = 21.562mL

d.) volume of metal in the flask = 5.356mL

e.) density of the metal = 12.644g/mL

Step-by-step explanation:

a.) mass of metal in the flask = (mass of flask + metal) - mass of empty flask

= 100.356 - 32.634 = 67.722g

b.) mass of water in the flask = (mass of flask when filled with metal and water) - (mass of flask when filled with metal alone)

= 121.860 - 100.356 = 21.504g

c. volume of the water in the flask :

in order to calculate the volume of water in the flask, the density formula is used as follows:

density = mass ÷ volume

volume = mass ÷ density.

where:

Density of water = 0.9973 g/mL

Mass of water as calculated above = 21.504g

∴ volume of water = 21.504 ÷ 0.9973 = 21.562mL

d.) volume of the metal in the flask:

Next, to calculate the volume of the metal in the flask:

volume of flask = volume of metal + volume of water

∴ volume of metal = volume of flask - volume of water

where:

volume of flask = 26.918mL (given)

volume of water = 21.562mL (calculated above)

∴ volume of metal = 26.918 - 21.562 = 5.356mL

e.) density of the metal:

Density = mass ÷ volume

where:

mass of metal = 67.722g ; volume of metal = 5.356mL

∴ Density of metal = 67.722 ÷ 5.356 = 12.644g/mL

4 0
3 years ago
Please I'm GIVING 40 POINTS FOR REAL ANSWER
Charra [1.4K]

Answer:

x = 14

< A = 58 degrees

< B = 52 degrees

< C = 70 degrees

Step-by-step explanation:

Recall that the addition of the three internal angles of a triangle must render 180 degrees, then we can write:

<A + <B + <C = 180

and now replace with the algebraic expressions given for each angle:

2(x + 15) + 3 x + 10 + 5 x = 180

eliminate parenthesis

2 x + 30 + 3 x + 10 + 5 x = 180

combine like terms

10 x + 40 = 180

subtract 40 from both sides

10 x = 140

divide both sides y 10 to isolate x

x = 14

Now that we know x, we can calculate each of the angles using the fiven expressions:

< A = 2 (x + 15) = 2 (14 + 15) = 2 * 29 = 58 degrees

< B = 3 x + 10 = 3 * 14 + 10 = 52 degrees

< C = 5 x = 5 * 14 = 70 degrees

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