Answer:
The original fraction is
.
Step-by-step explanation:
Solution,
Let the fraction be'
'.
Where 'x' is the numerator and 'y' is the denominator.
Now according to question, if 2 is added to both the numerator and denominator the value of the fraction becomes 1/2.
So, framing the above sentence in equation form, we get;

On using cross multiplication method, we get;

Now according to question, if 2 is Subtracted to both the numerator and denominator the value of the fraction becomes 1/3.
So, framing the above sentence in equation form, we get;

On using cross multiplication method, we get;

Now Substituting the equation 1 in equation 1 we get;

Now Substituting the value of x in equation 1 we get;

Hence The original fraction is
.