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EastWind [94]
3 years ago
11

If the product of two positive fractions a and b is 15/56, find three pairs for possible values for a and b

Mathematics
2 answers:
Elina [12.6K]3 years ago
5 0
All you have to do is find pairs of factor for both 15 and 56
e.g. 1,15   3,5 
      1.56    2, 28   4, 14

so three possibilities could be
1/1 x 15/56
3/4 x 5/14 
1/2 x 15/28
love history [14]3 years ago
5 0

Answer

Find out the three pairs for possible values for a and b .

To prove

As given

The\ product\ of\ two\ positive\ fractions\ a\ and\ b\ is\ \frac{15}{56} .

i.e it is written in the form.

a\times b = \frac{15}{56}

When

a = \frac{3}{2} , b = \frac{5}{28}

Than

\frac{3\times 5}{2\times 28} = \frac{15}{56}

When

a = \frac{3}{4} , b = \frac{5}{14}

Than

\frac{3\times 5}{4\times 14} = \frac{15}{56}

When

a = \frac{1}{2} , b = \frac{15}{28}

Than

\frac{1\times 15}{2\times 28} = \frac{15}{56}

Hence proved



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