Ask question

Ask question

All categories

2 years ago

11

A rectangle as shown has a length of 0.9 centimeters and a width of 0.4 cm. A circle is drawn inside that touches the rectangle

at two points.
What is the area to the shaded region in the rectangle.

2 answers:

adelina 88 [10]2 years ago

7 0

Well if u round to the nearest hundred it is 0.23

Arada [10]2 years ago

6 0

Answer:

it should be 0.23 cm when rounded to the nearest hundredth

You might be interested in

Solve for x: |4x + 12| = 16

JulijaS [17]

4x+12=16
4x=4
x=1

or

-(4x+12)=16
-4x-12=16
-4x=28
x=-7

answer Choice C is correct

6 0

3 years ago

Read 2 more answers

X²+Y²=250 and XY=117<br> What are the values of X and Y?

yan [13]

Answer:

<h3> x = -9, y = -13 </h3><h3> or x = 13, y = 9</h3><h3> or x = -13, y = -9</h3><h3> or x = 9, y = 13</h3>

Step-by-step explanation:

$x^2+y^2=250\\\\x^2-2xy+y^2+2xy=250\\\\(x-y)^2=250-2xy\\\\(x-y)^2=250-2\cdot117\\\\ (x-y)^2=16\\\\x-y=4\qquad\qquad\vee\qquad \qquad x-y=-4\\\\x=4+y \qquad\qquad \vee\qquad\qquad x=-4+y\\\\(y+4)y=117\qquad\vee\qquad\quad (y-4)y=117\\\\y^2+4y-117=0\qquad\vee\qquad y^2-4y-117=0\\\\y=\dfrac{-4\pm\sqrt{4^2-4(-117)}}{2\cdot1}\qquad\vee\qquad y=\dfrac{4\pm\sqrt{4^2-4(-117)}}{2\cdot1}\\\\y=\dfrac{-4\pm\sqrt{16+468}}{2}\qquad\ \ \vee\qquad y=\dfrac{4\pm\sqrt{16+468}}{2}$

$y_1=\dfrac{-4-22}{2}\ ,\quad y_2=\dfrac{-4+22}{2}\ ,\quad y_3=\dfrac{4-22}{2}\ ,\quad y_4=\dfrac{4+22}{2}\\\\y_1=-13\ ,\qquad y_2=9\ ,\qquad\quad\qquad\ y_3=-9\ ,\qquad y_4=13\\\\x_{1,2}=4+y_{1,2}\qquad\qquad\qquad\qquad\qquad x_{3,4}=-4+y_{3,4}\\\\x_1=-9\ ,\qquad x_2=13\ ,\qquad\quad\qquad x_3=-13\ ,\qquad x_4=9$

6 0

3 years ago

Which pair of angles shares Ray AG as a common side

Anastaziya [24]

BAF and FAD is the answer

4 0

3 years ago

8 - (-3) + 33 : (-3)

Lynna [10]

Answer:

Step-by-step explanation:

8-(-3)= 8+3+33=42

7 0

3 years ago

You have 2 buckets of water, inside the 1st bucket the temperature of the water is 25ºC, inside the 2nd bucket the water is 25ºF

Elanso [62]

The first bucket,because when we convert the both values in same units , we will observe that the temperature of first bucket is higher and second bucket is lower alternatively the kinetic energy in first bucket is higher and everything in it would move fast.

7 0

2 years ago