Answer:
Given system of equations:
To solve by substitution, equate the equations and solve for x:
Therefore, the x-values of the solution are 
and 
.
To find the y-values of the solution, substitute the found values of x into the functions:
Therefore, the solutions to the given system of equations are:
and 
-2x + 6 = 30 - 6x
--> -2x + 6x = 30 - 6
<span>--> 4x = 24
</span><span>--> x = 24/4
</span><span>--> x = 6</span>
The negative exponents that are in the numerator pass to positive if the base is moved to the denominator, and the negative exponents that are in the denominator pass to positive if the base is moved to the numerator.
The the answer is the option B: xx^4 / y^2 y^6
Answer:
a. LK = 4√3, JL= 4√6
b. PQ = 10√3, RP = 5√3
Step-by-step explanation:
a. LK =4√3,
LK=KJ= 4√3
sin(45°) = opposite/hypotenuse
hypotenuse (JL)= opposite/sin 45° = 4√3/√2/2 = 8√3/√2 = 8√3√2/2 = 4√6
b.
cos 30° = adjacent/hypotenuse = QR/PQ = 15/PQ
cos 30° = 15/PQ
PQ = 15/cos 30° = 15/√3/2)= 30/√3 = 30√3/3 = 10√3
tan 30° = opposite/adjacent = RP/QR
√3/3 = RP/QR
√3/3 = RP/15
RP = √3*15/3 = 5√3
