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nika2105 [10]
3 years ago
15

Gabrielle wants to tile a room with an area of 320 square feet. The width of the room is 4/5 it's length. What are the length an

d width of the room?

Mathematics
1 answer:
vampirchik [111]3 years ago
8 0
I hope this helps you

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Yes, of course you can! 
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3 years ago
Jack has a rectangular sticker that is 6 centimeters long and 4 centimeters wide.
Solnce55 [7]
Its c because 6*4 = 24
Thats how you find the area
8 0
3 years ago
Match each equation with its solution set. Tiles a2 − 9a + 14 = 0 a2 + 9a + 14 = 0 a2 + 3a − 10 = 0 a2 + 5a − 14 = 0 a2 − 5a − 1
sattari [20]
We have that

N 1)
a²<span> − 9a + 14 = 0 
</span>

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(a² − 9a)=-14

Complete the square  Remember to balance the equation by adding the same constants to each side 

(a² − 9a+20.25)=-14+20.25

Rewrite as perfect squares

(a-4.5)²=6.25--------> (a-4.5)=(+/-)√6.25

a1=4.5+√6.25-----> a1=7

a2=4.5-√6.25-----> a2=2

the solution problem N 1 is the pair {7, 2}


N 2) 

a²<span> + 9a + 14 = 0
</span>

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(a² + 9a)=-14

Complete the square  Remember to balance the equation by adding the same constants to each side 

(a² +9a+20.25)=-14+20.25

Rewrite as perfect squares

(a+4.5)²=6.25--------> (a+4.5)=(+/-)√6.25

a1=-4.5+√6.25-----> a1=-2

a2=-4.5-√6.25-----> a2=-7

the solution problem N 2 is the pair {-2,-7}

N 3) 

a² + 3a − 10 = 0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(a² + 3a)=10

Complete the square  Remember to balance the equation by adding the same constants to each side 

(a² + 3a+2.25)=10+2.25

Rewrite as perfect squares

(a+1.5)²=12.25------> (a+1.5)=(+/-)√12.25

a1=-1.5+√12.25-----> a1=2

a2=-1.5-√12.25-----> a2=-5

the solution problem N 3 is the pair {2, -5}


N 4)

a²<span> + 5a − 14 = 0
</span>

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(a² + 5a) =14

Complete the square  Remember to balance the equation by adding the same constants to each side 

(a² + 5a+6.25) =14+6.25

Rewrite as perfect squares

(a+2.5)² =20.25-------> (a+2.5)=(+/-)√20.25

a1=-2.5+√20.25-----> a1=2

a2=-2.5-√20.25-----> a2=-7

the solution problem N 4 is the pair {2, -7}


N 5) 

a² − 5a − 14 = 0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(a² − 5a)=14

Complete the square  Remember to balance the equation by adding the same constants to each side 

(a² − 5a+6.25)=14+6.25

Rewrite as perfect squares

(a-2.5)²=2025--------> (a-2.5)=(+/-)√20.25

a1=2.5+√20.25-----> a1=7

a2=2.5-√20.25-----> a2=-2

the solution problem N 5 is the pair {7, -2}

3 0
2 years ago
Read 2 more answers
HELPP HELPP HELPP HELPP HELP PLZ
iogann1982 [59]

Answer:

Volume= 216 cubic yards

Surface area: 276 square yards

Step-by-step explanation:

Find volume of rectangular prism:

V= lxwxh

V= 3x18x4

= 216 cubic yards

Find surface area:

SA= 2 x (front/back area) + 2 x (right/left area) and 2 x ( bottom/top area)

Front and Back Area:

A= l x w

A = 18 x 3

= 54 square yards

Right/ left Area:

4 x 3

= 12 square yards

Top/ Bottom Area:

18 x 4

= 72 square yards

54^2+12^2+72^2

= 108+24+144

=276 square yards

8 0
3 years ago
Read 2 more answers
Difference of 10 and a number W is no more than eight
algol [13]
10 - nw is less than or equal to 8

n = number


4 0
3 years ago
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