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luda_lava [24]
3 years ago
15

1 poir

Mathematics
2 answers:
podryga [215]3 years ago
4 0

The given options are:

  • (A)x+y = 20
  • (B)7 apps and 14 movies
  • (C)x-y= 20
  • (D)y=-x+ 20
  • (E)8 apps and 12 movies
  • (F)xy= 20

Answer:

  • (A)x+y = 20
  • (D)y=-x+ 20
  • (E)8 apps and 12 movies

Step-by-step explanation:

If Elizabeth has a combined total of 20 apps and movies.

Where:

Number of apps=x

Number of Movies =y

Then:

Their total,

  • x+y=20 (Option A)

If we subtract x from both sides

x+y-x=-x+20

  • y=-x+20 (Option D)

In Option E

8 apps and 12 movies  add up to 20. Therefore, this could also apply.

USPshnik [31]3 years ago
3 0

Answer:

y= -x+20  and 8 apps and 12 movies

Step-by-step explanation:

Just took the test and these two were the only two that were right.  I don't know why x+y=20 was not correct but it wasn't.   Good luck!

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Answer:

C. X+3x=36

Step-by-step explanation:

1. If you add the x's to get: 4x=36

2. Do division to get 9.

3. if you plug in 9 in the original,and multiply: 9+27=36

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Answer:

1: A) 12 meters

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The equation of the graph shown plotted in the coordinate plane is y = x + 4. What statement is not true about this graph? A. Ea
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Definately option C

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  • So in function every domain has its unique range.
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Question number 8. Prove that 3 + √5 is an irrational number.​
Marina86 [1]

Answer :

Let's assume the opposite of the statement i.e., 3 + √5 is a rational number.

\\  \sf \: 3 +  \sqrt{5}  =  \frac{a}{b}   \\  \\   \qquad \: \tiny \sf{(where \:  \: a \:  \: and \:  \: b \:  \: are \:  \: integers \:  \: and \:  \: b \:  \neq \: 0)} \\

\\  \sf \:  \sqrt{5}  =  \frac{a}{b}  - 3 =  \frac{a - 3b}{b}  \\

Since, a, b and 3 are integers. So,

\\ \sf \:  \frac{p - 3b}{b}  \\  \\  \qquad \tiny \sf{ \: (is \:  \: a \:  \: rational \:  \: number \:) } \\

Here, it contradicts that √5 is an irrational number.

because of the wrong assumption that 3 + √5 is a rational number.

\\

Hence, 3 + √5 is an irrational number.

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3 years ago
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