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Sergio039 [100]
3 years ago
14

Maya needs 54 cubic foot of soll for her garden, She already has 4,5 cubic feet of

Mathematics
1 answer:
nikitadnepr [17]3 years ago
3 0
The answer is A, let me know if you need an explanation
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In ΔTUV, t = 560 inches, v = 400 inches and ∠V=19°. Find all possible values of ∠T, to the nearest degree
Serjik [45]

Answer:

27 and 153 degrees

Step-by-step explanation:

Delta math

6 0
3 years ago
3x- 5=1 what does x represent
V125BC [204]

Answer:

x=2

Step-by-step explanation:

3x=5+1

3x=6

x=6/3

x=2

8 0
3 years ago
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6z + 10= -2 solve this problem ​
nydimaria [60]

Answer:

z = -2

Step-by-step explanation:

6 0
2 years ago
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A librarian has 4 identical copies of Hamlet, 3 identical copies of Macbeth, 2 identical copies of Romeo and Juliet, and one cop
lesantik [10]

Answer:

The number of distinct arrangements is <em>12600</em><em>.</em>

Step-by-step explanation:

This is a permutation type of question and therefore the number of distinguishable permutations is:

n!/(n₁! n₂! n₃! ... nₓ!)

where

  • n₁, n₂, n₃ ... is the number of arrangements for each object
  • n is the number of objects
  • nₓ is the number of arrangements for the last object

In this case

  • n₁ is the identical copies of Hamlet
  • n₂ is the identical copies of Macbeth
  • n₃ is the identical copies of Romeo and Juliet
  • nₓ = n₄ is the one copy of Midsummer's Night Dream

Therefore,

<em>Number of distinct arrangements =  10!/(4! × 3! × 2! × 1!)</em>

<em>                                                         = </em><em>12600 ways</em>

<em />

Thus, the number of distinct arrangements is <em>12600</em><em>.</em>

4 0
3 years ago
Exact = 50 Approximate = 45
Nikitich [7]

Answer:

Approximate of error = 11.11 % (Approx.)

Step-by-step explanation:

Given:

Exact value = 50

Approximate value = 45

Find:

Approximate of error

Computation:

Approximate of error = [(Exact value - Approximate value)/Approximate value]100

Approximate of error = [(50 - 45)/45]100

Approximate of error = [(5)/45]100

Approximate of error = [0.11111]100

Approximate of error = 11.11 % (Approx.)

3 0
3 years ago
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