Let,
- Mass of the steel be 108x
- Mass of the copper be 7x
- Then, Total mass = 108x + 7x = 115x
Given,
- Total mass of the coin = 230 mg
That means,
⇛ Total mass of the coin = 230 mg
⇛ 115x = 230 mg
⇛ x = 230 mg/115
⇛ x = 2 mg
Then,
- Mass of the steel = 108(2) = 216 mg
- Mass of the copper = 7(2) = 14 mg
☁️ ANSWER - 14 mg (Mass of copper)
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First, find out how much ribbon there is.
3 x 12 = 36
Now, see how many times you can divde that by 8.
36 can only be divided by 8 four times, and there would be 4 inches of ribbon left.
So, you would be able to make 4 bows, with 4 inches of ribbon remaining.
The answer is C because if you put
Find the reflected two points which are:
They're just flipped equations
Answer:
its point D hope this helps :)
Answer:
69
Step-by-step explanation:
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