One positive integer is 5 times another positive integer and their product is 320. What are the positive integers?
1 answer:
Answer:
The integers are (x, y) = (40, 8).
Step-by-step explanation:
x = 5y
xy = 320
Substitute the first equation into the second equation.
(5y)(y) = 320
5y^2 = 320
y^2 = 64
y = 8 (y must be positive)
The integers are (x, y) = (40, 8).
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The answer to the question
1 is the magnitude of this question bro because it is process
Answer:
Example of matrices such hat 
Step-by-step explanation:
We have two give example of 2×2 matrices such that AB = AC BUT B ≠ C.
Example:
![A =\left[\begin{array}{ccc}1&0\\0&0\end{array}\right]\\\\B = \left[\begin{array}{ccc}1&1\\1&2\end{array}\right], C = \left[\begin{array}{ccc}1&1\\1&3\end{array}\right]](https://tex.z-dn.net/?f=A%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%260%5C%5C0%260%5Cend%7Barray%7D%5Cright%5D%5C%5C%5C%5CB%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%261%5C%5C1%262%5Cend%7Barray%7D%5Cright%5D%2C%20C%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%261%5C%5C1%263%5Cend%7Barray%7D%5Cright%5D)
Solving:
![AB = \left[\begin{array}{ccc}1+0&1+0\\0+0&0+0\end{array}\right] = \left[\begin{array}{ccc}1&1\\0&0\end{array}\right]](https://tex.z-dn.net/?f=AB%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%2B0%261%2B0%5C%5C0%2B0%260%2B0%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%261%5C%5C0%260%5Cend%7Barray%7D%5Cright%5D)
![AC = \left[\begin{array}{ccc}1+0&1+0\\0+0&0+0\end{array}\right] = \left[\begin{array}{ccc}1&1\\0&0\end{array}\right]](https://tex.z-dn.net/?f=AC%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%2B0%261%2B0%5C%5C0%2B0%260%2B0%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%261%5C%5C0%260%5Cend%7Barray%7D%5Cright%5D)
Hence,
48 claims are rejected and 272 are accepted...
explanation
320/100= 3.2
3.2 * 15=48
320-48=272
Hello :
2x²-10 = 2(x-0)²-10 <span>in vertex form</span>
