y= x^2 - 6x-7
Vertex = -b /2a
b= -6
a= 1
-(-6)/2(1)= 3
x= 3
Use the substitution method to find y
y= (3)^2-6(3)-7
(3)(3)-18-7
9-25
y= -16
Vertex is (3, 16)
Find x- intercept (y= 0)
y= x^2 - 6x-7
(x-7)(x+1)
x-7= 0
Move -7 to the other side. Sign changes from -7 to 7
x-7+7= 0+7
x= 7
x+1= 0
Move +1 to the other side. Sign changes from +1 to -1
x+1-1= 0-1
x= -1
Answer :B. Vertex: (3, -16); Intercepts: x=-1,7
Answer:
IDK
Step-by-step explanation:
Step-by-step explanation:
hsq=psq+bsq
csq=48sq+14sq
csq=2304+196
c=50cm
where,
sq=square
Answer:
3
Step-by-step explanation:
4(9)/ 12
36/12
3/1
3
therefore 3 is the the sum
