Describe how the graph of each function is related to the graph of its parent function.

Mathematics

1 answer:

adelina 88 [10]3 years ago

4 0

Answer:

5. reflection in y=0, translation 1 up

6. translation 4 right

7. translation 1 left, 2 down

Step-by-step explanation:

For parent function f(x), the transformation ...

g(x) = a·f(x -h) +k

represents a vertical scaling by a factor of "a", a translation to the right by an amount "h", and a translation upward by an amount "k". When "a" is negative, it represents a reflection across the x-axis.

5. a=-1, h=0, k=1. Reflection across the x-axis, then translation upward 1 unit.

6. a=1, h=4, k=0. Translation to the right 4 units.

7. a=1, h=-1, k=-2. Translation 1 unit left and 2 units down.

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In January 2011 the rate of VAT increased from 17.5% to 20%

Sergio [31]

Answer:

Difference between in price of a car due to increase in VAT is $375.

Step-by-step explanation:

Since e have given that

Price of car = $15000

Rate of VAT = 17.5%

So, Amount of tax becomes

So, Total Price he has to pay is given by

but According to question,

Rate of VAT = 20%

So, Amount of tax becomes

So, Total price he has to pay is given by

Difference between both the price due to increase in VAT is given by

Hence, difference between in price of a car due to increase in VAT is $375.

7 0

3 years ago

PLEASE HELP.

solniwko [45]

recall that the radius is the distance from the center of a circle to any point on the circle.

we know the center is at -16,-14, and we know that -8,-8 is a point on the circle, so the distance between both must be the radius.

$\bf ~~~~~~~~~~~~\textit{distance between 2 points}
\\\\
(\stackrel{x_1}{-16}~,~\stackrel{y_1}{-14})\qquad
(\stackrel{x_2}{-8}~,~\stackrel{y_2}{-8})\qquad \qquad
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
\stackrel{radius}{r}=\sqrt{[-8-(-16)]^2+[-8-(-14)]^2}
\\\\\\
r=\sqrt{(-8+16)^2+(-8+14)^2}\implies r=\sqrt{8^2+6^2}
\\\\\\
r=\sqrt{100}\implies \boxed{r=10}
\\\\[-0.35em]
\rule{34em}{0.25pt}$

$\bf \textit{equation of a circle}\\\\
(x- h)^2+(y- k)^2= r^2
\qquad
center~~(\stackrel{-16}{ h},\stackrel{-14}{ k})\qquad \qquad
radius=\stackrel{10}{ r}
\\\\\\\
[x-(-16)]^2+[y-(-14)]^2=10^2\implies \blacktriangleright (x+16)^2+(y+14)^2=100 \blacktriangleleft$