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3 years ago

6

Telescopes are instruments that can magnify very small objects. Truth or false?

2 answers:

lutik1710 [3]3 years ago

6 0

False. that’s a microscope

OlgaM077 [116]3 years ago

5 0

Answer:

False

Explanation:

Magnifying glasses magnify small objects.

Telescopes magnify large objects from far away

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How does mass affect potential energy?

Andreyy89

What i would say: The amount of gravitational potential energy an object has depends on its height and mass. The heavier the object and the higher it is above the ground, the more gravitational potential energy it holds. Gravitational potential energy increases as weight and height increases.

Hope this helps! :)

8 0

2 years ago

How do you rewrite 4 5/7 as an improper fraction. in steps

noname [10]

Answer:

33/7

Multiply the denominator of the fraction by the whole number.

Add this result to the numerator of the fraction

answer becomes the numerator of the improper fraction.

Explanation:

6 0

2 years ago

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Hot, molten rock deep below Earth’s surface is called lava mantle rock parent rock magma

Rashid [163]

Answer:

I think it is Magma

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3 years ago

A compound with a total of four carbons. A straight chain across the bottom of three carbons with all single bonds. There is a m

AleksandrR [38]

I know the answer. It is 2 straight chains. lLOL

6 0

3 years ago

5.11 g of MgSO₄ is placed into 100.0 mL of water. The water's temperature increases by 6.70°C. Calculate ∆H, in kJ/mol, for the

cupoosta [38]

Answer: Thus ∆H, in kJ/mol, for the dissolution of MgSO₄ is -66.7 kJ

Explanation:

To calculate the entalpy, we use the equation:

$q=mc\Delta T$

where,

q = heat absorbed by water = ?

m = mass of water = ${\text {volume of water}}\times {\text {density of water}}=100.0ml\times 1.00g/ml=100.0g$

c = heat capacity of water = 4.186 J/g°C

$\Delta T$ = change in temperature = $6.70^0C$

$q=100.0g\times 4.184J/g^0C\times 6.70^0C=2803.3J=2.8033kJ$

Sign convention of heat:

When heat is absorbed, the sign of heat is taken to be positive and when heat is released, the sign of heat is taken to be negative.

The heat absorbed by water will be equal to heat released by $MgSO_4$

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass = 5.11 g

Molar mass = 120 g/mol

Putting values in above equation, we get:

$\text{Moles of }MgSO_4=\frac{5.11g}{120g/mol}=0.042mol$

0.042 moles of $MgSO_4$ releases = 2.8033 kJ

1 mole of $MgSO_4$ releases = $\frac{2.8033 kJ}{0.042}\times 1=66.7kJ$

Thus ∆H, in kJ/mol, for the dissolution of MgSO₄ is -66.7 kJ

3 0

3 years ago