What determines the ratio of ions of an ionic compound? ( see screenshot for options)

What is the temperature if 2L of 3moles HCl react with 2atm?

swat32

Answer:

$T=16K=-256.8\°C$

Explanation:

Hello!

In this case, according to the gas laws, we would be able to assume HCl can be modeled as an ideal gas for this calculation purpose; in such a way, we use the following equation to compute the temperature:

$PV=nRT\\\\T=\frac{PV}{nR}$

In such a way, we plug in moles, volume and pressure to obtain:

$T=\frac{2atm*2L}{3mol*0.08206\frac{atm*L}{mol*K}}\\\\T=16K=-256.8\°C$

Best regards!

8 0

3 years ago

Which noble gas is the exception to the octet (Stable-8) Rule

Taya2010 [7]

The exception to an octet of electrons would be the first noble gas, Helium, which only has two valence electrons. This primary affects the element hydrogen, which forms stable compounds by achieving two valence electrons.

8 0

4 years ago

A 2.241-g sample of nickel reacts with oxygen to form 2.852 g of the metal oxide.

nlexa [21]

Answer:

The empirical formula is = $NiO$

Explanation:

Given that:- Mass of nickel = 2.241 g

Mass of the oxide formed = 2.852 g

Mass of the oxygen reacted = Mass of the oxide formed - Mass of nickel = 2.852 g - 2.241 g = 0.611 g

Molar mass of nickel = 58.6934 g/mol

Moles of nickel = $\frac{2.241}{58.6934}\ mol$ = 0.03818 mol

Molar mass of oxygen = 15.999 g/mol

Moles of nickel = $\frac{0.611}{15.999}\ mol$ = 0.03818 mol

Taking the simplest ratio for Ni and O as:

0.03818 : 0.03818 = 1 : 1

<u>The empirical formula is = $NiO$ </u>

4 0

4 years ago

Calculate the volume in litres (L) of 1.41 mol of gas at 68.0 kPa and 27.00 °C (gas constant R = 8.314 J mol K-.).

Pani-rosa [81]

Answer:

3.) 51.7 L

Explanation:

To find the volume, you need to use the Ideal Gas Law:

PV = nRT

In the equation,

-----> P = pressure (kPa)

-----> V = volume (L)

-----> n = moles

-----> R = Ideal Gas constant (8.314 kPa*L/mol*K)

-----> T = temperature (K)

First, you need to convert the temperature from Celsius to Kelvin. Then, you can plug the given values into the equation and simplify to find "V".

P = 68.0 kPa R = 8.314 kPa*L/mol*K

V = ? L T = 27.00 °C + 273 = 300 K

n = 1.41 moles

PV = nRT <----- Ideal Gas Law

(68.0 kPa)V = (1.41 moles)(8.314 kPa*L/mol*K)(300 K) <----- Insert values

(68.0 kPa)V = 3516.822 <----- Multiply right side

V = 51.7 <----- Divide both sides by 68.0

3 0

1 year ago

A diffusion coefficient KG was determined for the diffusion of a gas A through a stagnant film B [KG = 0.88 mol//h-ft2-atm].

Angelina_Jolie [31]

Explanation: