2H2+O2→2H2O
We have to be aware that the number of atoms are the same on both reactant side and product side.
Explanation:
Methane molecule is depicted here
<u>Given:</u>
Volume of the unknown monoprotic acid (HA) = 25 ml
<u>To determine: </u>
The concentration of the acid HA
<u>Explanation:</u>
The titration reaction can be represented as-
HA + NaOH → Na⁺A⁻ + H₂O
As per stoichiometry: 1 mole of HA reacts with 1 mole of NaOH
At equivalence point-
moles of HA = moles of NaOH
For a known concentration and volume of added NaOH we have:
moles of NaOH = M(NaOH) * V(NaOH)
Thus, the concentration of the unknown 25 ml (0.025 L) of HA would be-
Molarity of HA = moles of HA/Vol of HA
Molarity of HA = M(NaOH)*V(NaOH)/0.025 L
The air we breathe is a mixture and for number 10th they are elements.
