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Anvisha [2.4K]
3 years ago
7

An analysis of a 4.2-gram sample of a compound is found to contain 54.76 percent sodium (Na) and 45.24 percent fluorine (F).  De

termine the empirical formula of the compound
Chemistry
2 answers:
Natali [406]3 years ago
7 0

Answer:

NaF

Explanation:

If the 54.76% of the sample is sodium and 45.24% is fluorine. Mass of each atom is:

Na: 4.2g × 0.5476 = <em>2.3g</em>

F: 4.2g × 0.4524 = <em>1.9g</em>

In moles:

Na: 2.3g × (1mol / 22.99g) = <em>0.1 moles</em>

F: 1.9g × (1mol / 19) = <em>0.1 moles</em>

As empirical formula is defined as the simplest whole-number ratio of atoms in a compound, the ratio of Na:F is:

0.1 / 0.1 = 1. Thus, empirical formula is:

<em>NaF</em>

<em></em>

Dvinal [7]3 years ago
6 0
The answer to this question is:

An analysis of a 4.2-gram sample of a compound is found to contain 54.76 percent sodium (Na) and 45.24 percent fluorine (F).  Determine the empirical formula of the compound?.
<span>"NaF"
</span>
Hoped This Helped, <span> Hgibore
Your Welcome :) </span>
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For the following reaction, 35.4 grams of zinc oxide are allowed to react with 6.96 grams of water . zinc oxide(s) + water(l) --
IRISSAK [1]

Answer:

m_{Zn(OH)_2}=38.4g

Explanation:

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In this case, for the undergoing chemical reaction:

ZnO(s)+H_2O(l)\rightarrow Zn(OH)_2

We evaluate the yielded moles of zinc hydroxide by each reactant as shown below:

n_{Zn(OH)_2}^{by ZnO}=35.4gZnO*\frac{1molZnO}{81.38gZnO}*\frac{1molZn(OH)_2}{1molZnO}  =0.435molZn(OH)_2\\\\n_{Zn(OH)_2}^{by H_2O}=6.96gH_2O*\frac{1molH_2O}{18.02gH_2O}*\frac{1molZn(OH)_2}{1molH_2O}  =0.386molZn(OH)_2

In such a way, since the water yields a smaller amount of zinc hydroxide we conclude it is the limiting reactant so the maximum mass is computed below:

m_{Zn(OH)_2}=0.386molZn(OH)_2*\frac{99.424 gZn(OH)_2}{1molZn(OH)_2} \\\\m_{Zn(OH)_2}=38.4g

Because the water limits the yielded amount of zinc hydroxide.

Best regards!

5 0
3 years ago
a nuclide of 64/29 cu absorbs a positron. witch is the resulting atom? (A) 65/29Cu (B) 63/29 CU (C) 64/28Ni (D) 64/30 Zn
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Answer : Option D) Zn^{64}_{30}

Explanation : When a positron is getting absorbed it means it will be e^{+1}_{0} so, the Cu^{64}_{29} will get converted;

So, the whole reaction will be;

Cu^{64}_{29} + e^{+1}_{0} ----> Zn^{64}_{30}.

This will convert the whole element of Cu will get changed into Zn. As, it absorbs by the positron, the atomic number gets increased from 29 to 30.

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3 years ago
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konstantin123 [22]

Answer:

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Explanation:

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8 0
3 years ago
An artifact originally had 16 grams of​ carbon-14 present. the decay model upper a equals 16 e superscript negative 0.000121 ta=
xeze [42]

<u>Given:</u>

Initial amount of carbon, A₀ = 16 g

Decay model = 16exp(-0.000121t)

t = 90769076 years

<u>To determine:</u>

the amount of C-14 after 90769076 years

<u>Explanation:</u>

The radioactive decay model can be expressed as:

A = A₀exp(-kt)

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Based on the given data :

A = 16 * exp(-0.000121*90769076) = 16(0) = 0

Ans: Based on the decay model there will be no C-14 left after 90769076 years

3 0
4 years ago
Read 2 more answers
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Answer:

The final volume of the balloon is = 28.11 L

Explanation:

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Initial volume V_{1} = 22.4 L

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We know that

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Put all the values in above formula we get

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V_{2} = 28.11 L

This is the final volume of the balloon.

8 0
3 years ago
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