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2 years ago

A wheel for Lisa's bike has a diameter of 24 inches. What is the circumference, C, in inches? Use 3.14 for π

Mathematics

1 answer:

julsineya [31]2 years ago

3 0

Answer:

75.36 inches

Step-by-step explanation:

C = π·d

C = 3.14(24)

C = 75.36

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In simplified exponential notation, the expression x^3•x^-4•x=

alexandr1967 [171]

Since all of the bases (x) are equal you just add the exponents.

(The x has an exponent of 1)

3 + -4 + 1

-1 + 1

0

Since the answer is 0 it is x^0

And any number or variable set to the power of 0 equals 1, therefore...

ANSWER: x^3 • x^-4 • x = 1

Hope this helps!

6 0

3 years ago

Tia measured the daily high temperature in Kats, Colorado for each of the 30 days in April. She then created both a dot plot and

lara31 [8.8K]

*see attachment below showing the dot plot and box plot created by Tia

Answer:

Dot plot

Step-by-step explanation:

In a dot plot, the temperature of a day is represented by 1 dot. There are 30 dots on the box plot shown in the attachment that was made by Tia.

This dot plot display makes it easier to find how many days had a temperature that is higher than 15°.

Thus, from the dot plot, we have:

2 dots representing 2 days having a temperature of 16°C each

2 days also have daily temperature of 17°C

2 days have temperature of 18°C as well, and

1 day has temperature of 19° C.

Therefore, the number of days that had a temperature above 15°C is 7 days.

3 0

3 years ago

Read 2 more answers

If you flip a coin 100 times and get 74 heads and 26 tails. What is the probability that the next flip results in a tail?

ollegr [7]

It will always be a 50 50 chance

4 0

3 years ago

Read 2 more answers

EXAMPLE 1 (a) Find the derivative of r(t) = (2 + t3)i + te−tj + sin(6t)k. (b) Find the unit tangent vector at the point t = 0. S

Tatiana [17]

The correct question is:

(a) Find the derivative of r(t) = (2 + t³)i + te^(−t)j + sin(6t)k.

(b) Find the unit tangent vector at the point t = 0.

Answer:

The derivative of r(t) is 3t²i + (1 - t)e^(-t)j + 6cos(6t)k

(b) The unit tangent vector is (j/2 + 3k)

Step-by-step explanation:

Given

r(t) = (2 + t³)i + te^(−t)j + sin(6t)k.

(a) To find the derivative of r(t), we differentiate r(t) with respect to t.

So, the derivative

r'(t) = 3t²i +[e^(-t) - te^(-t)]j + 6cos(6t)k

= 3t²i + (1 - t)e^(-t)j + 6cos(6t)k

(b) The unit tangent vector is obtained using the formula r'(0)/|r(0)|. r(0) is the value of r'(t) at t = 0, and |r(0)| is the modulus of r(0).

Now,

r'(0) = 3t²i + (1 - t)e^(-t)j + 6cos(6t)k; at t = 0

= 3(0)²i + (1 - 0)e^(0)j + 6cos(0)k

= j + 6k (Because cos(0) = 1)

r'(0) = j + 6k

r(0) = (2 + t³)i + te^(−t)j + sin(6t)k; at t = 0

= (2 + 0³)i + (0)e^(0)j + sin(0)k

= 2i (Because sin(0) = 0)

r(0) = 2i

Note: Suppose A = xi +yj +zk

|A| = √(x² + y² + z²).

So |r(0)| = √(2²) = 2

And finally, we can obtain the unit tangent vector

r'(0)/|r(0)| = (j + 6k)/2

= j/2 + 3k

8 0

3 years ago

Can anyone solve this for me ? please

Firdavs [7]

Answer:

Step-by-step explanation:

5 0

2 years ago