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Yuri [45]
3 years ago
12

An overseas telephone call costs 0.36 per minute how much would a 6-Minute call cost??

Mathematics
1 answer:
vovikov84 [41]3 years ago
7 0

This problem states that an overseas telephone call costs 0.36 cents per minute. They spend 6 minutes on the call.

All you have to do is multiply 0.36 cents on 6 minutes.

Your answer is $2.16

Hope this helped! :D

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Clarissa has a budget of $1,200 a month to spend for rent and food. She has already spent $928 this month. Which inequality repr
shtirl [24]

Answer:

1200-928 = 272 for the rest of the month Clarissa has to spend.

Step-by-step explanation:

So we don't want her to go over her budget so we wouldn't choose a greater than option for her so eliminate the first option and the last option. Now we just have the middle two. We want to keep it under 1200 but theres nothing wrong with spending that exact amount each month so I would pick x less than or equal to 272, since we can still equal the total of less than the total and not go over. Option 2 or B.

6 0
3 years ago
Read 2 more answers
Let x1 = 12, y1 = 15, and y2 = 3. Let y vary inversely with x. Find x2.
vladimir1956 [14]

Answer:

x2 = 60

Step-by-step explanation:

If the variables x and y are inversely proportional, the product x * y is a constant.

So using x1 and y1 we can find the value of this constant:

x1 * y1 = k

12 * 15 = k

k = 180

Now, we can use the same constant to find x2:

x2 * y2 = k

x2 * 3 = 180

x2 = 180 / 3 = 60

So the value of x2 is 60.

3 0
3 years ago
Need help with these math questions please.
Bas_tet [7]

Answer:

8 - 2π square units.

π/16 - 1/8 square units.

6π - 9√3 square units.

Step-by-step explanation:

The area of the square = 2√2 * 2√2

= 2*2*2

= 8.

The area of the circle = πr^2

= π * [ ( 2√2)/ 2) ]^2

=  π (√2)^2

=  2π.

Second Question:

The area of the circle = π(1/2)^2 = π/4.

Finding the area of the square:

1^2 = 2x^2

x^2 = 1/2

So the area of the square = 1/2

So the area of the red part = 1/4 ( π/4 - 1/2).

= π/16 - 1/8.

Third question

Area of the circle = 6^2 * π = 36π.

Now 60 degrees is 1/6 of 360 degrees so the are of the sector is 6π.

The area of the segment = 6π -  0.5 * 6^2 sin 60

= 6π - 18√3/2

= 6π - 9√3 square units.

6 0
3 years ago
Problem number 26 of the Rhind Papyrus says: Find a quantity such that when it is added to StartFraction 1 Over 4 EndFraction of
Rzqust [24]

Answer:

x=12

Step-by-step explanation:

For the given situation , a quantity x is added to \frac{1}{4} x gives 15.

We can set up equation as

x+\frac{1}{4}x=15

Multiply each term by 4 on both sides to get rid the denominator.

It gives,

4 x+x=60

Now, combine like terms

5 x=60

Divide both sides by 5

x=12.

6 0
4 years ago
A trapezoid has a height of 6 inches, an area of 120 square inches, and one base measuring 13 inches. Find the length of the oth
kirill [66]

Answer:

27

Step-by-step explanation:

Givens

b1 = 13

b2 = ?

h = 6

Area = 120

Formula

Area = (b1 + b2) * h/2         Multiply by 2

2Area = (b1 + b2)*h           Divide by h

2Area/h = b1 + b2              Subtract b1 from both sides

2Area/h - b1 = b2

Solution

2*120 / 6 - 13 = b2

40 - 13 = b2

b2 = 27

It is always handy to solve an equation in the form that finds the unknown on one side. It makes the solution much easier.

6 0
3 years ago
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