2 years ago

HELP ILL MARI YOU BRAINLYIST

Mathematics

1 answer:

SIZIF [17.4K]2 years ago

8 0

Answer:

though I told him he is in love you to be able and he will have a test done to you guys at the hospital and the other

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Joe spent 167 on camping gear. Rounded to the nearest hundrerd about how much money did he spend

soldi70 [24.7K]

Answer:

200

Step-by-step explanation:

If the second digit of 167 is 5 or above it will be rounded to 200.

6 0

2 years ago

3)Solve F(x) for the given domain. F(x) = x 2 + 3x - 2 F(-1) = a)-4 b)-6 c)2

Alja [10]

The answer to the question is a) -4.

6 0

2 years ago

Could someone please help me with these systems. I have to use substitution.

FromTheMoon [43]

Isolate one term (x or y) in one of the equations

6x+6y=0
6x=-6y
X= -1y

Substitute x=-y into the other equation

-7(-y) + 2y =18

7y + 2y =18

9y=18

Y=2

Substitute y=2 into 6x+6y=0

6x + 6(2) = 0

6x + 12=0

6x= -12

X = -2

8 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B16%20%7Bx%7D%5E%7B4%7D%20%7D%20%20-%20%20%5Csqrt%5B3%5D%7B128x%7D%20" id="

NemiM [27]

Kudos to the poster on the typeset math.

With cube roots we don't have to worry that things are positive.

$\sqrt[3]{16 x^4} - \sqrt[3]{128 x} = \sqrt[3]{2^4 x^4} - \sqrt[3]{2^7 x} = \sqrt[3]{2^3 x^3 2x} - \sqrt[3]{4^3 2 x} = 2x\sqrt[3]{2x} - 4\sqrt[3]{2 x}$

$= (2x-4)\sqrt[3]{2 x}$

3 0

2 years ago

Please help thanks :)

Aleksandr-060686 [28]

Answer: 1 song is 1.3 the total cost of 25 songs would be 33.75

6 0

3 years ago

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