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3 years ago

HELP ILL MARI YOU BRAINLYIST

Mathematics

1 answer:

SIZIF [17.4K]3 years ago

8 0

Answer:

though I told him he is in love you to be able and he will have a test done to you guys at the hospital and the other

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46 2/3% of 28 please i need to know answer an work

Bogdan [553]

First, it would help to put 46 and 2/3 into an improper fraction: 140/3.

Then, since this is a percent, we put that improper fraction over 100: (140/3)/100 = 140/300.

Finally, we multiply this answer by 28 since "of" means multiply:

(140/300) * 28 = 196/15 = 13 1/15

8 0

3 years ago

PLEASE HELP!

Kitty [74]

You can reword the two equations as:

-5x-y=15 (Divide original value by 3)
-2x+6y=6

Then use elimination to find x:

-30x-6y=90 (Multiply by 6 to get y values to be same to cancel out)
-2x+6y=6

You're left with:

-32x=96. Which can then be solved to find x which is -3.

Then plug back in

-2x+6y=6

Now to: -2(-3)+6y=6.

Which reduces to 6+6y=6. So y=0.

To graph them, just reword the equations (yes once again) so that y is in front.

y=-5x-15 and y=(1/3)x+1

8 0

3 years ago

Henry bought 1/4 pounds of screws and 2/5 of backstop build a skateboard ramp. What is the total weight of the screws and nails

nexus9112 [7]

It equals 0.65 pounds

6 0

3 years ago

Polygon ABCD is reflected and dilated to give polygon PQRS. The coordinates of the preimage are (2, 2), (6, 8), (12, 8), and (16

HACTEHA [7]

Answer: The scale factor of the dilation is 0.5.

Explanation:

It is given that ABCD is polygon which is reflected and dilated , then we get PQRS.

The vertices of ABCD are (2, 2), (6, 8), (12, 8), and (16, 2) respectively. The vertices of image PQRS are (11, 15),(9, 12), (6, 12), and (4, 15) respectively.

The reflection affects the coordinates but does not affect the length of the sides.

But when we talk about dilation it affects the length of sides according to the scale factor or a constant factor.

If a line segment AB is dilated by scale factor k then length of A'B' is k times length of AB.

$|A'B'|=k\times |AB|$ .... (1)

So we have to find any side length of preimage and the side length of that side in image. it means we have to find AB and PQ.

Use distance formula to find the side length.

$D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$AB=\sqrt{(8-2)^2+(6-2)^2}=\sqrt{36+16}=2\sqrt{13}$

$PQ=\sqrt{(9-11)^2+(12-15)^2}=\sqrt{4+9}=\sqrt{13}$

It is noticed that the size of side in preimage is $2\sqrt{13}$ and the size of same side in image is $\sqrt{13}$ .

Using equation (1), we get

$\sqrt{13}=k \times 2\sqrt{13}$

$k=\frac{1}{2}$

$k=0.5$

Hence, the value of scale factor is 0.5.

7 0

3 years ago

Read 2 more answers

równanie zmiany prędkość autokaru poruszającego się po prostym odcinku szosy i rozpoczynającego hamowanie od szybkości 20m/s ma

Rasek [7]

Answer:

s = 22.5 m

Step-by-step explanation:

the equation for the speed change of a coach moving along a straight section of the road and starting braking at a speed of 20 m / s has the form v (t) = 25-5t. Using integral calculus, determine the coach's braking distance.

v (t) = 25 - 5 t

at t = 0 , v = 20 m/s

Let the distance is s.

$s =\int v(t) dt\\\\s =\int (25 - 5t)dt\\\\s= 25 t - 2.5 t^2 \\$

Let at t = t, the v = 20

So,

20 = 25 - 5 t

t = 1 s

So, s = 25 x 1 - 2.5 x 1 = 22.5 m

3 0

2 years ago