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3 years ago

5

A drawer contains 8 blue socks,8 black socks,and 4 white socks.socks are picked at random.explain why the events picking a blue

sock and then another blue sock are dependent.then find the probability.

1 answer:

xeze [42]3 years ago

6 0

The probability would be like 14/95

You might be interested in

Factor Trinomials:

notka56 [123]

Answer:

1. $2(x+2)(x+5)$

2. $8(x+4)^{2}$

Step-by-step explanation:

<u>Problem #1:</u>

1. Find the GCF (Greatest Common Factor)

$GCF = 2$

2. Factor out the GCF and simplify.

$2(x^{2} +7x+10)$

3. Factor $x^{2} +7x+10$

<u>Which two numbers add up to 7 and multiply to 10?</u>

2 and 5

<u>Rewrite the expression using the above.</u>

$(x+2)(x+5)$

4. Done!

$2(x+2)(x+5)$

<u>Problem #2:</u>

1. Find the GCF (Greatest Common Factor)

$GCF=8$

2. Factor out the GCF and simplify.

$8(x^{2} +8x+16)$

3. Use the perfect square formula. $a^{2} +2ab+b^{2} =(a+b)^{2}$

$a = x\\b=4$

$(x+4)^{2}$

4. Done!

$8(x+4)^{2}$

8 0

2 years ago

In a completely randomized experimental design, three brands of paper towels were tested for their ability to absorb water. Equa

arlik [135]

Answer:

Yes. At this significance level, there is evidence to support the claim that there is a difference in the ability of the brands to absorb water.

Step-by-step explanation:

<em>The question is incomplete:</em>

<em>The significance level is 0.05.</em>

<em>The data is:</em>

<em>Brand X: 91, 100, 88, 89</em>

<em>Brand Y: 99, 96, 94, 99</em>

<em>Brand Z: 83, 88, 89, 76</em>

We have to check if there is a significant difference between the absorbency rating of each brand.

Null hypothesis: all means are equal

$H_0:\mu_x=\mu_y=\mu_z$

Alternative hypothesis: the means are not equal

$H_a: \mu_x\neq\mu_y\neq\mu_z$

We have to apply a one-way ANOVA

We start by calculating the standard deviation for each brand:

$s_x^2=30,\,\,s_y^2=6,\,\,s_z^2=35.33$

Then, we calculate the mean standard error (MSE):

$MSE=(\sum s_i^2)/a=(30+6+35.33)/3=71.33/3=23.78$

Now, we calculate the mean square between (MSB), but we previously have to know the sample means and the mean of the sample means:

$M_x=92,\,\,M_y=97,\,\,M_z=84\\\\M=(92+97+84)/3=91$

The MSB is then:

$s^2=\dfrac{\sum(M_i-M)^2}{N-1}\\\\\\s^2=\dfrac{(92-91)^2+(97-91)^2+(84-91)^2}{3-1}\\\\\\s^2=\dfrac{1+36+49}{2}=\dfrac{86}{2}=43\\\\\\\\MSB=ns^2=4*43=172$

Now we calculate the F statistic as:

$F=MSB/MSE=172/23.78=7.23$

The degrees of freedom of the numerator are:

$dfn=a-1=3-1=2$

The degrees of freedom of the denominator are:

$dfd=N-a=3*4-3=12-3=9$

The P-value of F=7.23, dfn=2 and dfd=9 is:

$P-value=P(F>7.23)=0.01342$

As the P-value (0.013) is smaller than the significance level (0.05), the null hypothesis is rejected.

There is evidence to support the claim that there is a difference in the ability of the brands to absorb water.

3 0

3 years ago

Find the future value of 575 at 5.5% compounded quarterly for 5 years. Round to the nearest cent

Readme [11.4K]

Answer:

Future value = $755.61 ( to the nearest cent)

Step-by-step explanation:

The formula for calculating the future value of an invested amount compounded periodically for a number of years is given as:

$FV = PV (1+\frac{r}{n} )^{n*t}$

where:

FV = future value = ???

PV = present value = $575

r = interest rate in decimal = 5.5% = 0.055

n = number of compounding periods per year = quarterly = 4

t = time of investment = 5 years

∴ $FV = 575 (1+\frac{0.055}{4} )^{4*5}$

$FV = 575 (1+0.01375)^{20}\\FV = 575 (1.01375 )^{20}\\FV = 575 * 1.3141\\FV = 755.607$

∴ Future value = $755.61 ( to the nearest cent)

4 0

2 years ago

Write an<br> algebraic expression fh each verbal expression.

PtichkaEL [24]

Answer:

2×y^2

Step-by-step explanation:

i hope it helped you a lot. thankyou

4 0

3 years ago

14k=84 solve the equation and check your solution

UNO [17]

Answer:

k = 6

Step-by-step explanation:

14k=84

k = 84/14

k = 6

to check the equation:

14k ..we found that k is 6, so replace k with 6

14(6)

84 ......checked.

5 0

2 years ago