Answer: B
a median of a triangle is a line segment joining a vertex to the midpoint of the opposite side, thus bisecting that side.
Hope this helps!
Y = mx + b is the slope-intercept form of the equation of a line,
where m = slope, and b = y-intercept.
In problems 1 and 3, your equations are written in the y= mx + b form, so you can read the slope and y-intercept directly.
1.
m = -5/2
b = -5
3.
m = -1
b = 3
5.
For problem 5, you need to solve for y to put the equation
in y = mx + b form. Then you can read m and b just like we did
for problems 1 and 3.
4x + 16y = 8
16y = -4x + 8
y = -4/16 x - 8/16
y = -1/4 x - 1/2
m = -1/4
b = -1/2
Answers is
A'= -3,3
B'=4,-1
C'=-2,0
2(4x - 5) = 49
8x - 10 = 49
8x - 10 + 10 = 49 + 10
8x = 59
8x/8 = 59/8
x = 7.375
Answer:
35
Step-by-step explanation:
7 orchids can be lined as 7!. This means that for the first orchid of the line, you can select 7 options. When you place the first orchid, for the second option you can select among 6 since 1 orchid has already been placed. Similarly, for the 3rd orchid of the line, you have left 5 options. The sequence goes in this fashion and for 7 orchids, you have 7*6*5*4*3*2*1 possibilities. However, there is a restriction here. 3 of the orchids are white and 4 are levender. This means that it does not make a difference if we line 3 white orchids in an arbitrary order since it will seem the same from the outside. As a result, the options for lining the 7 orchids diminish. The reduction should eliminate the number of different lining within the same colors. Similar to 7! explanation above, 3 white orchids can be lined as 3! and 4 levender orchids can be lined as 4!. To eliminate these options, we divide all options by the restrictions. The result is:
= 35. [(7*6*5*4*3*2*1/(4*3*2*1*3*2*1)]