This is the concept of algebra, we are required to calculate the area cut out of a cylinder represented by the function x^2+z^2=36;
The equation of a circle is given by:
(x-a)^2+(y-b)^2=r^2
where;
(a,b) are the center of the circle;
r=radius of the circle
re-writing our equation we have:
x^2+z^2=36
(x-0)^2+(z-0)^2=6^2
this implies that the center of the circle is (0,0) and the radius is 6 units;
Therefore the area will be given by:
Area=πr^2
Area=π*6^2
Area=36π=113.1 sq. units
We have been given that in ΔHIJ, the measure of ∠J=90°, the measure of ∠I=29°, and JH = 88 feet. We are asked to find the length of IJ to the nearest tenth of a foot.
First of all, we will draw a right triangle using our given information as shown in the attachment.
We can see that in triangle HIJ, the side IJ is adjacent side to angle I and JH is opposite side to angle I.
We know that tangent relates opposite side of right triangle to adjacent side.





Upon rounding to nearest tenth, we will get:

Therefore, the length of the side IJ is approximately 258.8 units.
40,000 + 6,000 + 300 + 70 + 1
Step-by-step explanation:
