1/2 (3/2 y + 1/3) = -1/2 (y- 5/2)
1 answer:
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Answer:
cos(z) = .3846153846 and angle z = 67.38°
Step-by-step explanation:
Side UV is corresponding to side YX. Side VW is corresponding to side YZ. Side UW is corresponding to side XZ.
Starting with the first corresponding pair, we are told that side UV is 36, and that side YX is 3/5 of that. So side YX is
We are next told that side VW is 39, so side YZ is
In order to find the cos of angle z, we need the adjacent side, which is side XZ. Side XZ is 3/5 of side UW. Right now we don't know the length of side UW, so we find it using Pythagorean's Theorem:
and
so
UW = 15
Now we can say that side XZ is
The cos of an angle is the side adjacent to the angle (9) over the hypotenuse of the triangle (23.4) so our ratio is:
which divides to
cos(z) = .3846153846
If you need the value of the angle, use the inverse cosine function on your calculator in degree mode to find that
angle z = 67.38°
Answer:
Perimeter of one triangle is 65 dm
Perimeter of other triangle is 52 dm
Step-by-step explanation:
Please remember the concept
If sides are in the ratio of a:b
Then the area in the ratio of
It is given sum of their perimeter is 117.
Let the small triangle has perimeter as x.
So, perimeter of big triangle is 117-x.
So, we can set up equation as
Cross multiply
50(117-x)^2 =32x^2
Expand the left side
50=
Distribute the left side
684450-11700x+=
Subtract both sides and rewrite it
Solve this quadratic for x.
Divide both sides of the equation by 18 to simplify.
-650 x+38025=0
Now, if possible let's factor
Find two integers whose multiplication is 38025 but adds to -650.
-65 and -585 works.
So, we can rewrite it as
(x -65)(x-585) =0
Solve them using zero product property
x=65, x=585
So, x=65 works here.
So, perimeter of one triangle is 65 dm
Perimeter of other triangle is 117-65= 52 dm