A gram of NaOH required to neutralize 700 ml HCL is <u>84 grams.</u>
Neutralization or neutralization is a chemical response in which an acid and a base react quantitatively with each different. I
Moles of solute = Molarity × Liters of solution
= 3 × 0.7 L
= 2.1 mole
The molar mass of NaOH = 40
mass of NaOH = 40 × 2.1 g
=<u> 84 gram.</u>
A neutralization response may be described as a chemical reaction in which an acid and base quantitatively react together to shape salt and water as products. In a neutralization response, there's a combination of H+ ions and OH– ions that form water.
A neutralization response is when an acid and a base react to shape water and salt and includes the mixture of H+ ions and OH- ions to generate water. The neutralization of a sturdy acid and robust base has a pH equal to 7.
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Answer:
16.8128 grams of sodium azide is needed
Explanation:
2NaN3 = 2Na + 3N2
molar mass of NaN3 =
molar mass of N2
moles of N2 =
moles=mass/R.F.M
16.55÷42 = 0.3940
mole ratio=
2NaN3 : 3N2
3 = 0.3940
2=?
Mass of sodium azide =64×0.2627
=16.8126
Explanation:
its hard its either B or C i dont wanna be wrong;-;
The balanced chemical equation is Pb(NO3)2+ 2KI produces PbI2 + 2K(NO)3
.4 L of KI × (.375 mol/L of KI) × (1 mol of PbI2 / 2 mol of KI) × (461 g of PbI2/1 mol of PbI2)
=34. 6 g of PbI2 precipitate.
