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Mars2501 [29]
3 years ago
10

The length (L) of a simple pendulum is directly proportional to the square of the time period (T). Which type of graph can best

describe this relationship?
A. hyperbolic
B. inverse
C. linear with negative slope
D. linear with positive slope
E. quadratic
Chemistry
2 answers:
Marina86 [1]3 years ago
7 0

Answer:

E.quadratic

Explanation:

The length L of a simple pendulum is directly proportional to the square of the time time period

L=k T^2

k is the constant of proportionality

the above equation is quadratic in nature (power two) and the equation plotted on graph give parabolic shape.

hence the answer to the question is   E. quadratic

Lostsunrise [7]3 years ago
4 0
I believe it's E. Quadratic.
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Which of the following releases chemical energy?
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D. burning wood

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A small sample of methane burns, producing co2 and water vapor. as the hot gas mixture expands, it releases 120.0 kj of heat and
IceJOKER [234]

A small sample of methane burns, releasing 120.0 kJ of heat and doing 830.0 kJ of work. The total energy released is -950.0 kJ.

  • What is energy?

Energy is a property that is transferred to a physical system, recognizable in the performance of work and in the form of heat and light.

A small sample of methane undergoes combustion. As the hot gas mixture expands, it releases energy (E).

  • It releases 120.0 kJ of heat. By convention, when heat is released, we assign it a negative sign. Thus, q = -120.0 kJ.
  • It does 830.0 kJ of work. By convention, when the system does work on the surroundings, we assign it a negative sign. Thus, w = -830.0 kJ.

The change in the energy is the sum of the heat released and the work done.

ΔE = q + w = -120.0 kJ + (-830.0 kJ) = -950.0 kJ

A small sample of methane burns, releasing 120.0 kJ of heat and doing 830.0 kJ of work. The total energy released is -950.0 kJ.

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8 0
2 years ago
A solution is made containing 14.6g of CH3OH in 185g H2O.1. Calculate the mole fraction of CH3OH.2. Calculate the mass percent o
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Answer:

* x_{CH_3OH}=0.0425

* \%m/m_{CH_3OH}=7.31\%

* m=2.46m

Explanation:

Hello,

In this case, for the mole fraction of methanol we use the formula:

x_{CH_3OH}=\frac{n_{CH_3OH}}{n_{CH_3OH}+n_{water}}

Thus, we compute the moles of both water (molar mass 18 g/mol) and methanol (molar mass 32 g/mol):

n_{CH_3OH}}=14.6g*\frac{1mol}{32g}=0.456molCH_3OH \\\\n_{water}}=185g*\frac{1mol}{18g}=10.3molH_2O

Hence, mole fraction is:

x_{CH_3OH}=\frac{0.456mol}{0.456mol+10.3mol}\\\\x_{CH_3OH}=0.0425

Next, mass percent is:

\%m/m_{CH_3OH}=\frac{m_{CH_3OH}}{m_{CH_3OH}+m_{water}}*100\%\\\\\%m/m_{CH_3OH}=\frac{14.6g}{14.6g+185g}*100\%\\\\\%m/m_{CH_3OH}=7.31\%

And the molality, considering the mass of water in kg (0.185 kg):

m=\frac{n_{CH_3OH}}{m_{water}} =\frac{0.456mol}{0.185kg}\\ \\m=2.46m

Regards.

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