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2 years ago

The width of a piece of paper was 1/2. The area of the paper was 9/16. What was the length of the paper?

Mathematics

1 answer:

lutik1710 [3]2 years ago

7 0

Answer:

Length = 1.5

Step-by-step explanation:

L = A divided by W

L = .75 divided by .5 = 1.5

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The length L of a rectangle is 4 units more than its width W. The rectangle's are is 252 square units. A) Write the equation tha

jek_recluse [69]

Answer:

w=14

l=18

Step-by-step explanation:

To find the dimensions, create an equation for its area and solve for each using the area formula A = l*w. The dimensions given are A = 252, w for width and l= w+4 (4 more than the width).

$A = l*w\\252 = (w+4)*w\\252 = w^2+4w\\252+4 = w^2 +4w +4\\256 = (w+2)^2\\\sqrt{256} =\sqrt{(w+2)^2} \\16 = w+2\\16 = w+2\\14= w\\$

The width is 14 so the length is l=w+4 or l= (14)+4 =18

3 0

3 years ago

Determine the solutuon for x^2-3x-28>0

natita [175]

Answer:

x < -4 or x > 7.

Step-by-step explanation:

We first determine the critical points by solving x^2 - 3x - 28 = 0:

x^2 - 3x - 28 = 0

(x - 7)(x + 4) = 0

x = 7, - 4

so the critical points are -4 and 7.

Create a Table (pos = positive and neg = negative):

Value of x< - 4 -4 < x < 7 x > 7

---------------------|----------- |--------------------- |---------------------

x + 4 NEG POS POS

x - 7 NEG NEG POS

(x + 4)(x - 7) POS NEG POS

So the function is positive (>0) for x < -4 or x > 7.

You can also do this by drawing the graph of the function.

6 0

3 years ago

A golfers score after playing on friday was +2

jek_recluse [69]

The end of his round on Saturday was a -5, and the end of his round on Sunday was a 0.

6 0

2 years ago

Which piece of wood would be the shortest 1/3 1/4 2/5 or3/10

nadya68 [22]

3/10 that's what the answer is

3 0

3 years ago

Read 2 more answers

Evgen [1.6K]

Answer:

Null hypothesis $H_0; \mu=5$

Alternative hypothesis $H_a; \mu\neq 5$

Step-by-step explanation:

Consider the provided information.

The shower by an adult is 5 minutes.

The mean amount of time that college students spend in the shower is significantly different from 5 minutes. In a sample of 15 students, he found the average time was 4.29 minutes and the standard deviation was 0.75 minutes.

We need to determine the appropriate null and alternative hypotheses.

A null hypothesis is there is no statistical significance between the two variables.

An alternative hypothesis is there is a statistically significant relationship between two variables.

Therefore the required null and alternative hypothesis are:

Null hypothesis $H_0; \mu=5$

Alternative hypothesis $H_a; \mu\neq 5$

3 0

2 years ago