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3 years ago

Write in standard rorma y =2/3x-6

Mathematics

1 answer:

timurjin [86]3 years ago

3 0

Answer:

-2/3x+y=6

Step-by-step explanation:

Standard form is just x+y=n, so all that we have to do it get that x over by subtraction.

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Point B is on a line that has a slope of 2. Which of these could be the coordinates of another point on the line?

stealth61 [152]

I actually don't have enough information to complete this question but if you have a positive slope the line goes either up and right or down and left but when it is negative it goes down left or up right.

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3 years ago

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Simplify: ( 1^0+2^1+3^2) ÷ 22/ 5^0

Aleksandr-060686 [28]

Step-by-step explanation:

( 1 + 2 + 9 ) ÷ 22/ 1

12 ÷ 22

6 ÷ 11

cc: Anything raised to the power of zero is 1

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3 years ago

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What is 55 x 25 equaled to

nikitadnepr [17]

Answer:

1375

Step-by-step explanation:

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3 years ago

A ship leaves port at noon and has a bearing of S29oW. The ship sails at 20 knots. How many nautical miles south and how many na

ira [324]

Answer:

Approximately $58.2\; \text{nautical miles}$ (assuming that the bearing is ${\rm S$29^{\circ}$W}$ .)

Step-by-step explanation:

Let $v$ denote the speed of the ship, and let $t$ denote the duration of the trip. The magnitude of the displacement of this ship would be $v\, t$ .

Refer to the diagram attached. The direction ${\rm S$29^{\circ}$W}$ means $29^{\circ}$ west of south. Thus, start with the south direction and turn towards west (clockwise) by $29^{\circ}$ to find the direction of the displacement of the ship.

The hypothenuse of the right triangle in this diagram represents the displacement of the ship, with a length of $v\, t$ . The dashed horizontal line segment represents the distance that the ship has travelled to the west (which this question is asking for.) The angle opposite to that line segment is exactly $29^{\circ}$ .

Since the hypotenuse is of length $v\, t$ , the dashed line segment opposite to the $\theta = 29^{\circ}$ vertex would have a length of:

$\begin{aligned}& \text{opposite (to $\theta$)} \\ =\; & \text{hypotenuse} \times \frac{\text{opposite (to $\theta$)}}{\text{hypotenuse}} \\ =\; & \text{hypotenuse} \times \sin (\theta) \\ =\; & v\, t \, \sin(\theta) \\ =\; & v\, t\, \sin(29^{\circ})\end{aligned}$ .

Substitute in $\begin{aligned} v &= 20\; \frac{\text{nautical mile}}{\text{hour}}\end{aligned}$ and $t = 6\; \text{hour}$ :

$\begin{aligned} & v\, t\, \sin(29^{\circ}) \\ =\; & 20\; \frac{\text{nautical mile}}{\text{hour}} \times 6\; \text{hour} \times \sin(29^{\circ}) \\ \approx\; & 58.2\; \text{nautical mile}\end{aligned}$ .

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2 years ago

The area of a triangle is 3.6 cm2. If the triangle has a base of 6 cm, what is the height?

Allisa [31]

The area of a triangle can be calculated using the following equation:

A = 1/2 (B x H)

Where B is the dimension of the base and H is the height of the triangle.

Since the area is known and the dimension of the base is also known, substitute the values into the equation to find the height:

3.6 cm2 = 1/2 (6 cm) (H)

Solving yields an answer of 1.2 cm. Hence the height is 1.2 cm.

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3 years ago