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yanalaym [24]
3 years ago
12

Write in standard rorma y =2/3x-6

Mathematics
1 answer:
timurjin [86]3 years ago
3 0

Answer:

-2/3x+y=6

Step-by-step explanation:

Standard form is just x+y=n, so all that we have to do it get that x over by subtraction.

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Which statement represents the expression?
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Answer:

Which statement represents the expression?

24−8÷4

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B. the difference of 24 and 8 divided by 4

C. 24 minus the quotient of 8 divided by 4

D. 24 minus 4 divided by 8

The answer is <em><u>a. 24 minus 8 divided by 4</u></em>

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5 0
3 years ago
Read 2 more answers
The figure is an isosceles trapezoid. How many lines of reflectional symmetry does the trapezoid have?
Natalija [7]

Reflectional symmetry is the mirror image of one side of image to the other when we divide the image. In other words it is one half of image is the reflection of other half of image.

In isosceles trapezoid, the length of the sides are same . the bases are not same.

When we draw a vertical line in the middle of  isosceles trapezoid, the left side of the image is the reflection of right side .

So there is only one line of reflection symmetry.


4 0
3 years ago
Read 2 more answers
I was never good with fractions, could someone help?
tangare [24]

Answer:

Thus, the answer is:

\left \{ {{x=4} \atop {y=2}} \  \atop {z=-4}} \right

Step-by-step explanation:

Considering the system of equations

\left \{ {{x+y+z=2} \atop {4x+y+z=14}} \  \atop {x-y+4z=-14}} \right\}

Rewrite the system in matrix form and solve it by Gaussian Elimination (Gauss-Jordan elimination)

\left \{ {{x+y+z=2} \atop {4x+y+z=14}} \  \atop {x-y+4z=-14}} \right\}\rightarrow \left[\begin{array}{ccc}1&1&1:2\\4&1&1:14\\1&-1&4:-14\end{array}\right]

R2 - 4 R1 → R2 (multiply 1 row by 4 and subtract it from 2 row); R3 - 1 R1 → R3 (multiply 1 row by 1 and subtract it from 3 row)

  \left[\begin{array}{ccc}1&1&1:2\\0&-3&-3:6\\0&-2&3:-16\end{array}\right]

R2 / -3 → R2 (divide the 2 row by -3)

\left[\begin{array}{ccc}1&1&1:2\\0&1&1:-2\\0&-2&3:-16\end{array}\right]

R1 - 1 R2 → R1 (multiply 2 row by 1 and subtract it from 1 row); R3 + 2 R2 → R3 (multiply 2 row by 2 and add it to 3 row)

\left[\begin{array}{ccc}1&0&0:4\\0&1&1:-2\\0&0&5:-20\end{array}\right]

R3 / 5 → R3 (divide the 3 row by 5)

\left[\begin{array}{ccc}1&0&0:4\\0&1&1:-2\\0&0&1:-4\end{array}\right]

R2 - 1 R3 → R2 (multiply 3 row by 1 and subtract it from 2 row)

\left[\begin{array}{ccc}1&0&0:4\\0&1&0:2\\0&0&1:-4\end{array}\right]

Thus, the answer is:

\left \{ {{x=4} \atop {y=2}} \  \atop {z=-4}} \right

Make a check:

4 + 2 + (-4) = 4 + 2 - 4 = 2

4·4 + 2 + (-4) = 16 + 2 - 4 = 14

4 - 2 + 4·(-4) = 4 - 2 - 16 = -14

Check completed successfully.

7 0
3 years ago
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