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Allushta [10]
2 years ago
8

Amy has 2 1/2 kilograms of grapes on the scale at the grocery store. She then puts an additional 50 grams of grapes on the scale

.
What is the total weight, in grams, of the grapes Amy puts on the scale at the grocery store?
Mathematics
2 answers:
Jet001 [13]2 years ago
7 0

Answer:

  • 2550 grams

Step-by-step explanation:

<u>Has on the scale</u>

  • 2 1/2 kg = 2 kg and 500 g = 2500 g

<u>Added</u>

  • 50 g

<u>Total</u>

  • 2500 + 50 = 2550 g
galben [10]2 years ago
7 0

Answer:

the total weight is 2550 grams

Step-by-step explanation:

2 1/2 kilograms=5/2×1000grams=2500grams

if 50 grams is added

total weight in grams =2500grams+50grams=2550grams

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Ivanshal [37]
I'm pretty sure it would be 4 5/6 - 3 2/3 = 1 1/6.
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3 years ago
What is the value of In e^4<br> a.0<br> b.1<br> c.2<br> d.4
Zina [86]
\large\begin{array}{l} \textsf{Computing the value of }\mathsf{\ell n (e^4).}\\\\\\ \textsf{Using logarithg properties:}\\\\ \textsf{(logarith of a power)}\\\\ \mathsf{\ell n(e^4)}\\\\ =\mathsf{4\cdot \ell n\,e}\qquad\quad\textsf{(but }\mathsf{\ell n\,e=1}\textsf{)}\\\\ =\mathsf{4\cdot 1}\\\\ =\mathsf{4}\qquad\checkmark\\\\\\\ \textsf{Correct answer: d. 4.} \end{array}


<span>If you're having problems understanding this answer, try seeing it through your browser: brainly.com/question/2113397


\large\textsf{I hope it helps.}
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Tags: <em>logarithm value compute power property natural log ln</em>

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3 years ago
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6 0
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maks197457 [2]

Step-by-step explanation:

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3 0
2 years ago
You want to obtain a sample to estimate a population proportion. At this point in time, you have no reasonable preliminary estim
Alenkasestr [34]

Answer:

n  = 400

Step-by-step explanation:

The formula for the error in our estimate is given by:

Standard Error :  √ ( p(1-p)/ n)

Error =  SE = Zα/2   √ ( p(1-p)/ n)  where

Zα/2= critical  value for 95% confidence level = 1.96

and we know our error is 3.5 %

But we do not the sample proportion p. Then what we can do is give an estimate of p in the absence of any other information.

In this case we will use p= 0.5 which is the value that maximizes the expression for the standard error :

if p = 0.8 then SE= 0.040

  p = 0.3 then SE =0.036

  p = 0.1 then  SE = 0.030

  p = 0.5 then SE = 0.050

Substituting

3.5/100  = 1.96 x  √ (( 0.5 x 0.5 ) /n )

3.5/ (100 x 1.96 x 0.5 ) = 1/ √n

0.0357 = 1 /√n

n = 20²

n = 400

3 0
3 years ago
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