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3 years ago

Which of the following equations describe the line (-6, 2) (-1, -4)? (Graph below)

1 answer:

8 0

I notice that all the choices are written in Point-Slope Formula. This is a key factor in answering your question.

So usually we solve for slope, plug into point-slope form, then solve for slope intercept.

We only have to do the first 2 steps:

Formula for slope: $\frac{y2-y1}{x2-x1}$
Plug in values: $\frac{-4-2}{-1-(-6)} = \frac{-6}{5}$
Slope: $- \frac{6}{5}$
Point-slope formula: $y - y1 = m(x-x1)$ where m is equivalent to slope.
Plug in values: $y -2 = -\frac{6}{5}(x + 6)$

We can also rewrite the equation like this using the other coordinates.

Plug in value: $y + 4 = - \frac{6}{5}(x + 1)$

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Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s). Consider this s

Brut [27]

Answer:

The solution of this system of equation is ( 3, - 8)

Step-by-step explanation:

1. Let's solve the system of equations:

First equation:

x + 2y = - 13

x = - 13 - 2y

Second equation:

12x + 5y = -4

12 * (- 13 - 2y) + 5y = - 4 (Replacing x with - 13 - 2y)

-156 -24y + 5y = - 4

-24y + 5y = - 4 + 156 (Like terms)

-19y = 152

y = - 152/19

y = -8 (Dividing by 19)

Solving x

x + 2y = -13

x + 2 (- 8 ) = - 13

x - 16 = - 13

x = - 13 + 16

x = 3

2. Proving that x = 3 and y = - 8 are correct:

12x + 5y = -4

12 * 3 + 5 * -8 = -4

36 - 40 = - 4

- 4 = - 4

We proved that x = 3 and y = - 8 are correct

8 0

3 years ago

Find exact values for sin θ and tan θ if cos θ = -4/9 and tan θ > 0.

julsineya [31]

Answer:

Part 1) $sin(\theta)=-\frac{\sqrt{65}}{9}$

Part 2) $tan(\theta)=\frac{\sqrt{65}}{4}$

Step-by-step explanation:

we have that

The cosine of angle theta is negative and the tangent of angle theta is positive

That means that the sine of angle theta is negative

step 1

Find $sin(\theta)$

we know that

$sin^{2}(\theta) +cos^{2}(\theta)=1$

we have

$cos(\theta)=-\frac{4}{9}$

substitute

$sin^{2}(\theta) +(-\frac{4}{9})^{2}=1$

$sin^{2}(\theta) +\frac{16}{81}=1$

$sin^{2}(\theta)=1-\frac{16}{81}$

$sin^{2}(\theta)=\frac{65}{81}$

square root both sides

$sin(\theta)=\pm\frac{\sqrt{65}}{9}$

Remember that

In this problem the sine of angle theta is negative

$sin(\theta)=-\frac{\sqrt{65}}{9}$

step 2

Find $tan(\theta)$

we know that

$tan(\theta)=\frac{sin(\theta)}{cos(\theta)}$

we have

$sin(\theta)=-\frac{\sqrt{65}}{9}$

$cos(\theta)=-\frac{4}{9}$

substitute the given values

$tan(\theta)=-\frac{\sqrt{65}}{9}:-\frac{4}{9}=\frac{\sqrt{65}}{4}$

3 0

4 years ago

PLEASE HELPPP i would really appreciate it :)

qaws [65]

Answer:

Y = - 12.55X1 + 276.52

Step-by-step explanation:

Given the data:

Age of child :(X) : 4, 6, 10, 13, 14, 17

Time (seconds) (Y) : 230, 205, 132, 119, 108, 62

Using technology, the linear regression equation obtained using the data Given is :

Y = - 12.55X1 + 276.52

Where :

Slope = - 12.55

Intercept = 276.52

This also indicates that a negative slope is present and hence a negative relationship between age of Child and time in seconds.

3 0

2 years ago

PLEASE HELP ASAP I WILL MARK AS BRAINLIEST

zimovet [89]

Answer:

The triangle because the other shapes have a square in them, also FYI you got your name in the photo

Step-by-step explanation:

4 0

3 years ago

HELP PLEASE! I don't understand and have been stuck on this problem for a whole hour. Please explain. Also, none of the answers

Lyrx [107]

The altitude is the mean proportional between the left and right parts of the hyptenuse

$\cfrac{FI}{GI} = \cfrac{GI}{HI} \ \ \Rightarrow \ \ \cfrac{FI}{15} = \cfrac{15}{16} \ \ \Rightarrow \ \ FI= \cfrac{15 \cdot 15 }{16} \approx 14.1$

Answer: 14.1

5 0

3 years ago

Read 2 more answers