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Alex777 [14]
3 years ago
11

A pet store advertises

Mathematics
1 answer:
nikklg [1K]3 years ago
5 0

Answer:

the answer is 1.99 I think im not sure I guessed

Step-by-step explanation:

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CAN SOMEBODY HELP WITH THIS QUESTION ASAP​
tia_tia [17]

Answer:

The rectangles are not similar

Step-by-step explanation:

In order to check whether they are similar, we need to take the ratio of their similar sides and ensure they are equal to a constant k.

Hence;

AB/PL = AD/LM = k

32/26 = 18/12 = k

16/13 = 9/6 = k

Since the scale factor is not the same, hence the rectangles are not the same.

6 0
2 years ago
Please answer for extra points !
MatroZZZ [7]

Answer:

the answer is D

Step-by-step explanation:

I don't know how to explain it very well but the line starts at 2 then ends at 8

6 0
2 years ago
Suppose that diameters of a new species of apple have a bell-shaped distribution with a mean of 7.25cm and a standard deviation
Ulleksa [173]

Answer:

95%

Step-by-step explanation:

5 0
2 years ago
5 cm<br> Find the total surface area of the<br> cylinder.<br> 10 cm
tatiyna

Answer: Area of a right circular Cylinder--- curved surface area -2πrh Total surface area -2πr(r+h),where 'r' is the radius of the circular surface and 'h' is the height of the cylinder.

3 0
3 years ago
Solve the system by using a matrix equation (Picture provided)
Katyanochek1 [597]

Answer:

Option b is correct (8,13).

Step-by-step explanation:

7x - 4y = 4

10x - 6y =2

it can be represented in matrix form as\left[\begin{array}{cc}7&-4\\10&-6\end{array}\right] \left[\begin{array}{c}x\\y\end{array}\right] = \left[\begin{array}{c}4\\2\end{array}\right]

A= \left[\begin{array}{cc}7&-4\\10&-6\end{array}\right]

X= \left[\begin{array}{c}x\\y\end{array}\right]

B= \left[\begin{array}{c}4\\2\end{array}\right]

i.e, AX=B

or X= A⁻¹ B

A⁻¹ = 1/|A| * Adj A

determinant of A = |A|= (7*-6) - (-4*10)

                                    = (-42)-(-40)

                                    = (-42) + 40 = -2

so, |A| = -2

Adj A=  \left[\begin{array}{cc}-6&4\\-10&7\end{array}\right]

A⁻¹ =  \left[\begin{array}{cc}-6&4\\-10&7\end{array}\right]/ -2

A⁻¹ =  \left[\begin{array}{cc}3&-2\\5&-7/2\end{array}\right]

X= A⁻¹ B

X=  \left[\begin{array}{cc}3&-2\\5&-7/2\end{array}\right] *\left[\begin{array}{c}4\\2\end{array}\right]

X= \left[\begin{array}{c}(3*4) + (-2*2)\\(5*4) + (-7/2*2)\end{array}\right]

X= \left[\begin{array}{c}12-4\\20-7\end{array}\right]

X= \left[\begin{array}{c}8\\13\end{array}\right]

x= 8, y= 13

solution set= (8,13).

Option b is correct.

3 0
3 years ago
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