The atmospheric pressure will be:
The pressure of the atmosphere resulting from the mercury column is 0.959 atm
What is atmospheric pressure?
The force that an object experiences from the weight of the air above it per unit area are known as atmospheric pressure.
Given: Height of mercury column = 729 mm Hg
To find: The pressure of the atmosphere
Calculation:
The atmospheric column resulting from the mercury column is calculated as follows:
1 atm =760 mm Hg
So, we can convert the 729 mm Hg to atm, and we get
Atmospheric pressure = 729 x 1 atm / 760 = 0.959 atm
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Answer: The rate of the loss of 
is 0.52M/s
Explanation:
Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.
The rate in terms of reactants is given as negative as the concentration of reactants is decreasing with time whereas the rate in terms of products is given as positive as the concentration of products is increasing with time.
Rate of disappearance of =![-\frac{1d[O_3]}{2dt}](https://tex.z-dn.net/?f=-%5Cfrac%7B1d%5BO_3%5D%7D%7B2dt%7D)
Rate of formation of 
=![+\frac{1d[O_2]}{3dt}](https://tex.z-dn.net/?f=%2B%5Cfrac%7B1d%5BO_2%5D%7D%7B3dt%7D)
![-\frac{1d[O_3]}{2dt}=+\frac{1d[O_2]}{3dt}](https://tex.z-dn.net/?f=-%5Cfrac%7B1d%5BO_3%5D%7D%7B2dt%7D%3D%2B%5Cfrac%7B1d%5BO_2%5D%7D%7B3dt%7D)
Rate of formation of = 
Thus Rate of disappearance of =![\frac{2d[O_2]}{3dt}=\frac{2}{3}\times 7.78\times 10^{-1}M/s=0.52M/s](https://tex.z-dn.net/?f=%5Cfrac%7B2d%5BO_2%5D%7D%7B3dt%7D%3D%5Cfrac%7B2%7D%7B3%7D%5Ctimes%207.78%5Ctimes%2010%5E%7B-1%7DM%2Fs%3D0.52M%2Fs)
Answer: A, B, D
Explanation:
all of these examples show matter moving from a high volume of matter, to low volume of matter. When the molecules of the paint, toast, and chemicals were released, they will try to disperse away from the high concentration
To complete the balancing of the following combustion reaction, we must do elemental balances. For C, there is 5 on the left side hence there should be 5 CO2. For H, H20 should be 9/2. Next we balance O. on theright side we find a total of 29/2. So the o2 on the left side should be 29/4. To have whole number stoich.coeff. we multiply the numbers by 4, hence answer is
4C5H9O + 9O2= 20 O2 + 18 H20.
